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The ionisation energy of H is 13.6 eV. C...

The ionisation energy of `H` is `13.6 eV`. Calculate the ionization energy of `Li^(2+)` ions.

A

`6hcR`

B

`2hcR`

C

`9hcR`

D

`hcR`

Text Solution

Verified by Experts

The correct Answer is:
C
Ionization energy `= (Rhc)Z^(2) = 9hcR` (Note : `E_(n) = - (RhcZ^(2))/(n^(2))`)
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