Home
Class 12
CHEMISTRY
If the % -s character in one Sb -H bond ...

If the % -s character in one Sb -H bond in `SbH_(3)` is 1.0 % . What is % p-character is the orbital occupied by its lone pair.

A

99

B

97

C

90

D

none

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the percentage of p-character in the orbital occupied by the lone pair in the molecule SbH₃, given that the % s-character in one Sb-H bond is 1.0%. ### Step-by-Step Solution: 1. **Identify the Hybridization**: - In SbH₃, there are three Sb-H bonds and one lone pair of electrons on the antimony (Sb) atom. - The steric number (SN) can be calculated as the number of sigma bonds plus the number of lone pairs. Here, SN = 3 (from three bonds) + 1 (from the lone pair) = 4. - A steric number of 4 corresponds to sp³ hybridization. 2. **Determine Total Hybridization Character**: - For sp³ hybridization, the hybrid orbitals are formed from one s orbital and three p orbitals. - The total percentage character of the hybrid orbitals must equal 100%. 3. **Calculate % s-character and % p-character**: - Given that the % s-character in one Sb-H bond is 1%, we can conclude that the hybridization involves 1 s orbital. - Since there are three p orbitals involved in sp³ hybridization, the % p-character can be calculated as follows: - Total % s-character = 1% (from one s orbital) - Total % p-character = 100% - % s-character - % p-character = 100% - 1% = 99%. 4. **Determine % p-character of the Lone Pair**: - The lone pair of electrons occupies an orbital that is also hybridized. Since we have established that the hybridization is sp³, the lone pair will also have the same % p-character as the hybrid orbitals. - Therefore, the % p-character in the orbital occupied by the lone pair is also 99%. ### Final Answer: The % p-character in the orbital occupied by the lone pair in SbH₃ is **99%**. ---
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

The percentage of p-character in the orbitals forming p-p bonds in P_4 is

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Two elements X and Y combined together to form a covalent compound. If % p-character is found to be 80% in a orbital then the hybridised state of central atom X for the orbital is :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Smallest Ohat(S)O bond angle is found in :

Two hybrid orbitals have a bond angle of 120^(@) . The percentage of p character in the hybrid orbital is nearly :-

Two hybrid orbitals have a bond angle of 120^(@) . The percentage of s-character in the hybrid orbitals is nealy:

Two hybrid orbitals have a bond angle of 120^(@) . The percentage of s-character in the hybrid orbitals is nealy:

If 20% of p is 10, what is 10% of p?

The bond angle between two hybrid orbitals is 180^(@) The percentage s-character of hybrid orbital is between .