Home
Class 12
PHYSICS
The side of a square is increasing at th...

The side of a square is increasing at the rate of 0.2 cm/sec. Find the rate of increase of the perimeter of the square.

A

`2bhat(j)`

B

`ahat(i)`

C

`(a-2b)hat(i)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`(dvec(r))/(dt)=ahat(i)-2bt hat(j)` at `t=0, (dvec(r))/(dt)=ahat(i)`
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

The side of a square in increasing at the rate of 0.2 cm/sec. Find the rate of increase of the perimeter of the square.

The side of a square is increasing at the rate of 0.1cm/sec. Find the rate of increase of its perimeter.

The side of a square is increasing at a rate of 3 cm/sec. Find the rate of increasing of its perimeter when the side of square is 5cm.

The side of a square is increasing at the rate of 0.2 cm/s. The rate of increase of perimeter w.r.t time is :

The side of a square is increasing at a rate of 4cm/sec. Find the rate of increase of its area when the side of square is 10 cm.

The side of an equilateral triangle is increasing at the rate of 10cm/sec . Find the rate of increase of its perimeter.

(i) The radius of a circle is increasing at the rate of 5 cm/sec. Find the rate of increasing of its perimeter. (ii) If the area of a circle increases at a constant rate, then show that the rate of increase of its circumference is inversely proportional to its radius.

The radius of a circle is increasing at the rate of 0.5cm/sec. Find the rate of increase of its circumference.

If the length of the diagonal of a square is increasing at the rate of 0.2 cm/sec, then the rate of increase of its area when its side is 30//sqrt(2) cm, is

At an instant the diagonal of a square is increasing at the rate of 0.2 cm/sec and the area is increasing at the rate of 6 cm^(2)//sec . At the moment its side, is