How many times divisions will occur in an isolated tip cell to form 128 cells ?

Options

A. 128
B. 127
C. 32
D. 7

Answer

To determine how many times divisions will occur in an isolated tip cell to form 128 cells, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the process of cell division**:
- In mitosis, one parent cell divides to produce two daughter cells. This is known as equational division.

2. **Establish the relationship between divisions and cell numbers**:
- Each division doubles the number of cells. Therefore, if we start with one cell, after one division, we will have 2 cells, after two divisions, we will have 4 cells, and so on.

3. **Use the formula for cell division**:
- The number of cells formed after 'n' divisions can be expressed as \(2^n\), where \(n\) is the number of divisions.

4. **Set up the equation**:
- We want to find out how many divisions are needed to reach 128 cells. Thus, we set up the equation:
\[ 2^n = 128 \]

5. **Rewrite 128 as a power of 2**:
- We know that \(128 = 2^7\). Therefore, we can rewrite our equation as:
\[ 2^n = 2^7 \]

6. **Solve for n**:
- Since the bases are the same, we can equate the exponents:
\[ n = 7 \]

7. **Conclusion**:
- Therefore, the number of divisions that will occur to form 128 cells is **7**.

### Final Answer:
The answer is **7**.

---