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A heated body maitained at T K emits the...

A heated body maitained at T K emits thermal radiation of total energy E with a maximum intensity at frequency v. The emissivity of the material is 0.5. If the temperature of the body be increased and maintained at temperature 3T K, then :-
(i) The maximum intensity of the emitted radiation will occur at frequency v/3
(ii) The maximum intensity of the emitted radiation will occur at frequency 3v.
(iii) The total energy of emitted radiation will become 81 E
(iv) The total energy of emitted radiation will become 27 E

A

i & ii

B

ii & iii

C

i & iv

D

i, ii & iv

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the effects of increasing the temperature of a heated body on the frequency of maximum intensity and the total energy of emitted radiation. ### Step-by-Step Solution: 1. **Understanding Wien's Displacement Law**: - Wien's Displacement Law states that the wavelength of maximum intensity (λ_max) is inversely proportional to the temperature (T). - Mathematically, it can be expressed as: \[ \lambda_{\text{max}} \propto \frac{1}{T} \] - Since frequency (ν) is inversely related to wavelength (ν = c/λ), we can infer that frequency is directly proportional to temperature: \[ \nu \propto T \] 2. **Calculating the New Frequency**: - Let the initial temperature be T and the initial frequency be ν. - When the temperature is increased to 3T, we can express the new frequency (ν') as: \[ \frac{\nu}{\nu'} = \frac{T}{3T} \implies \nu' = 3\nu \] - Therefore, the maximum intensity of the emitted radiation will occur at frequency **3ν**. 3. **Understanding the Total Energy of Emitted Radiation**: - The total energy (E) emitted by a black body is proportional to the fourth power of its temperature: \[ E \propto T^4 \] - If the initial energy at temperature T is E, then at temperature 3T, the new energy (E') can be calculated as: \[ E' = E \left(\frac{3T}{T}\right)^4 = E \cdot 3^4 = E \cdot 81 \] - Thus, the total energy of emitted radiation will become **81E**. ### Summary of Results: - The maximum intensity of the emitted radiation will occur at frequency **3ν** (Option ii). - The total energy of emitted radiation will become **81E** (Option iii). ### Final Answers: - (ii) The maximum intensity of the emitted radiation will occur at frequency **3ν**. - (iii) The total energy of emitted radiation will become **81E**. ---
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