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(sqrt(8)-sqrt(4)-sqrt(2)) equals :...

`(sqrt(8)-sqrt(4)-sqrt(2))` equals :

A

a) `2-sqrt(2)`

B

b) `sqrt(2)-2`

C

c) `2`

D

d) `-2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( \sqrt{8} - \sqrt{4} - \sqrt{2} \), we will simplify each square root step by step. ### Step 1: Simplify each square root - \( \sqrt{8} = \sqrt{4 \cdot 2} = \sqrt{4} \cdot \sqrt{2} = 2\sqrt{2} \) - \( \sqrt{4} = 2 \) - \( \sqrt{2} \) remains as \( \sqrt{2} \) ### Step 2: Substitute the simplified values back into the expression Now we can substitute the simplified square roots back into the expression: \[ \sqrt{8} - \sqrt{4} - \sqrt{2} = 2\sqrt{2} - 2 - \sqrt{2} \] ### Step 3: Combine like terms Next, we will combine the terms involving \( \sqrt{2} \): \[ 2\sqrt{2} - \sqrt{2} = (2 - 1)\sqrt{2} = 1\sqrt{2} = \sqrt{2} \] So, the expression now becomes: \[ \sqrt{2} - 2 \] ### Final Answer Thus, the value of the expression \( \sqrt{8} - \sqrt{4} - \sqrt{2} \) is: \[ \sqrt{2} - 2 \] ---
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KIRAN PUBLICATION-POWER, INDICES AND SURDS-Type -IV
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