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The value of ((0.67xx0.67xx0.67)-(0.33xx...

The value of `((0.67xx0.67xx0.67)-(0.33xx0.33xx0.33))/((0.67xx0.67)+(0.67xx0.33)+(0.33xx0.33))` is

A

`11`

B

`1.1`

C

`3.4`

D

`0.34`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \(\frac{(0.67 \times 0.67 \times 0.67) - (0.33 \times 0.33 \times 0.33)}{(0.67 \times 0.67) + (0.67 \times 0.33) + (0.33 \times 0.33)}\), we can follow these steps: ### Step 1: Identify the components We can rewrite the expression using powers: - The numerator becomes \(0.67^3 - 0.33^3\). - The denominator can be rewritten as \(0.67^2 + 0.67 \times 0.33 + 0.33^2\). ### Step 2: Apply the difference of cubes formula The difference of cubes formula states that: \[ A^3 - B^3 = (A - B)(A^2 + AB + B^2) \] Here, let \(A = 0.67\) and \(B = 0.33\). Therefore, we can express the numerator as: \[ (0.67 - 0.33)(0.67^2 + 0.67 \times 0.33 + 0.33^2) \] ### Step 3: Calculate \(A - B\) Calculate \(0.67 - 0.33\): \[ 0.67 - 0.33 = 0.34 \] ### Step 4: Calculate the denominator The denominator is already in the form of \(A^2 + AB + B^2\): \[ 0.67^2 + 0.67 \times 0.33 + 0.33^2 \] Calculating each term: - \(0.67^2 = 0.4489\) - \(0.33^2 = 0.1089\) - \(0.67 \times 0.33 = 0.2211\) Now, add these values: \[ 0.4489 + 0.2211 + 0.1089 = 0.7789 \] ### Step 5: Substitute back into the expression Now substitute back into the expression: \[ \frac{0.34 \times (0.67^2 + 0.67 \times 0.33 + 0.33^2)}{0.7789} \] Since the numerator simplifies to \(0.34 \times 0.7789\), we can cancel out \(0.7789\): \[ \frac{0.34 \times 0.7789}{0.7789} = 0.34 \] ### Final Answer Thus, the value of the expression is: \[ \boxed{0.34} \]
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