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The value of (root(3)(3.5)+root(3)(2.5))...

The value of `(root(3)(3.5)+root(3)(2.5)){(root(3)(3.5))^(2)-root(3)(8.75)+(root(3)(2.5))^(2)}` is :

A

A) `5.375`

B

B) `1`

C

C) `6`

D

D) `5`

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The correct Answer is:
To solve the expression \((\sqrt[3]{3.5} + \sqrt[3]{2.5}) \cdot \left((\sqrt[3]{3.5})^2 - \sqrt[3]{8.75} + (\sqrt[3]{2.5})^2\right)\), we can follow these steps: ### Step 1: Simplify the expression We can denote: - Let \( A = \sqrt[3]{3.5} \) - Let \( B = \sqrt[3]{2.5} \) Thus, the expression can be rewritten as: \[ (A + B) \cdot (A^2 - \sqrt[3]{8.75} + B^2) \] ### Step 2: Simplify \(\sqrt[3]{8.75}\) Notice that: \[ 8.75 = 3.5 \times 2.5 \] Therefore: \[ \sqrt[3]{8.75} = \sqrt[3]{3.5 \times 2.5} = \sqrt[3]{3.5} \cdot \sqrt[3]{2.5} = A \cdot B \] ### Step 3: Substitute back into the expression Now, we can substitute \(\sqrt[3]{8.75}\) back into the expression: \[ (A + B) \cdot (A^2 - A \cdot B + B^2) \] ### Step 4: Recognize the identity We can use the identity for the sum of cubes: \[ A^3 + B^3 = (A + B)(A^2 - AB + B^2) \] Thus: \[ A^2 - AB + B^2 = \frac{A^3 + B^3}{A + B} \] ### Step 5: Calculate \(A^3 + B^3\) Now we calculate \(A^3\) and \(B^3\): \[ A^3 = 3.5 \quad \text{and} \quad B^3 = 2.5 \] So: \[ A^3 + B^3 = 3.5 + 2.5 = 6 \] ### Step 6: Substitute back into the identity Now substituting back: \[ A + B = \sqrt[3]{3.5} + \sqrt[3]{2.5} \] Thus: \[ (A + B) \cdot (A^2 - AB + B^2) = (A + B) \cdot \frac{6}{A + B} = 6 \] ### Final Answer The value of the expression is: \[ \boxed{6} \]
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