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(64)^(-(2)/(3))xx((1)/(4))^(-2) is equal...

`(64)^(-(2)/(3))xx((1)/(4))^(-2)` is equal to :

A

`1`

B

`2`

C

`(1)/(2)`

D

`(1)/(16)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \((64)^{-\frac{2}{3}} \times \left(\frac{1}{4}\right)^{-2}\), we can follow these steps: ### Step 1: Rewrite the expression using the property of negative exponents Using the property that \(a^{-n} = \frac{1}{a^n}\), we can rewrite the expression: \[ (64)^{-\frac{2}{3}} = \frac{1}{(64)^{\frac{2}{3}}} \] Thus, the expression becomes: \[ \frac{1}{(64)^{\frac{2}{3}}} \times \left(\frac{1}{4}\right)^{-2} \] ### Step 2: Simplify \(\left(\frac{1}{4}\right)^{-2}\) Using the property of negative exponents again: \[ \left(\frac{1}{4}\right)^{-2} = 4^2 = 16 \] Now, our expression is: \[ \frac{1}{(64)^{\frac{2}{3}}} \times 16 \] ### Step 3: Calculate \((64)^{\frac{2}{3}}\) First, we find the cube root of 64. Since \(64 = 4^3\), we have: \[ (64)^{\frac{1}{3}} = 4 \] Now, squaring this result gives: \[ (64)^{\frac{2}{3}} = (4)^2 = 16 \] ### Step 4: Substitute back into the expression Now we substitute back into our expression: \[ \frac{1}{(64)^{\frac{2}{3}}} \times 16 = \frac{1}{16} \times 16 \] ### Step 5: Simplify the expression Finally, simplifying gives: \[ \frac{1 \times 16}{16} = 1 \] Thus, the final answer is: \[ \boxed{1} \] ---
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