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((0.96)^(3)-(0.1)^(3))/((0.96)^(2)+0.096...

`((0.96)^(3)-(0.1)^(3))/((0.96)^(2)+0.096+(0.1)^(2))` is simplified to :

A

`1.06`

B

`0.95`

C

`0.86`

D

`0.97`

Text Solution

AI Generated Solution

The correct Answer is:
To simplify the expression \(\frac{(0.96)^3 - (0.1)^3}{(0.96)^2 + 0.096 + (0.1)^2}\), we can follow these steps: ### Step 1: Identify the values Let \(a = 0.96\) and \(b = 0.1\). ### Step 2: Apply the difference of cubes formula The numerator can be simplified using the difference of cubes formula, which states: \[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \] Thus, we can rewrite the numerator: \[ (0.96)^3 - (0.1)^3 = (0.96 - 0.1)((0.96)^2 + (0.96)(0.1) + (0.1)^2) \] ### Step 3: Calculate \(a - b\) Now, calculate \(a - b\): \[ 0.96 - 0.1 = 0.86 \] ### Step 4: Calculate the second part of the numerator Next, we need to calculate \((0.96)^2 + (0.96)(0.1) + (0.1)^2\): - Calculate \((0.96)^2\): \[ (0.96)^2 = 0.9216 \] - Calculate \((0.96)(0.1)\): \[ (0.96)(0.1) = 0.096 \] - Calculate \((0.1)^2\): \[ (0.1)^2 = 0.01 \] Now, add these values together: \[ 0.9216 + 0.096 + 0.01 = 1.0276 \] ### Step 5: Substitute back into the expression Now substitute back into the expression: \[ \frac{(0.96 - 0.1)((0.96)^2 + (0.96)(0.1) + (0.1)^2)}{(0.96)^2 + (0.96)(0.1) + (0.1)^2} \] This simplifies to: \[ \frac{0.86 \cdot 1.0276}{1.0276} \] ### Step 6: Cancel out the common terms Since \((0.96)^2 + (0.96)(0.1) + (0.1)^2\) appears in both the numerator and denominator, we can cancel it out: \[ 0.86 \] ### Final Answer Thus, the simplified value of the expression is: \[ \boxed{0.86} \]
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