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((0.05)^(2)+(0.41)^(2)+(0.073)^(2))/((0....

`((0.05)^(2)+(0.41)^(2)+(0.073)^(2))/((0.005)^(2)+(0.041)^(2)+(0.0073)^(2))` is

A

`10`

B

`100`

C

`1000`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \(\frac{(0.05)^{2}+(0.41)^{2}+(0.073)^{2}}{(0.005)^{2}+(0.041)^{2}+(0.0073)^{2}}\), we can follow these steps: ### Step 1: Rewrite the numbers in terms of powers of 10 We can express the decimals as: - \(0.05 = 5 \times 10^{-2}\) - \(0.41 = 4.1 \times 10^{-1}\) - \(0.073 = 7.3 \times 10^{-2}\) - \(0.005 = 5 \times 10^{-3}\) - \(0.041 = 4.1 \times 10^{-2}\) - \(0.0073 = 7.3 \times 10^{-3}\) ### Step 2: Substitute these values into the expression The expression now becomes: \[ \frac{(5 \times 10^{-2})^{2} + (4.1 \times 10^{-1})^{2} + (7.3 \times 10^{-2})^{2}}{(5 \times 10^{-3})^{2} + (4.1 \times 10^{-2})^{2} + (7.3 \times 10^{-3})^{2}} \] ### Step 3: Simplify the squares Calculating the squares: - Numerator: - \((5 \times 10^{-2})^{2} = 25 \times 10^{-4}\) - \((4.1 \times 10^{-1})^{2} = 16.81 \times 10^{-2}\) - \((7.3 \times 10^{-2})^{2} = 53.29 \times 10^{-4}\) - Denominator: - \((5 \times 10^{-3})^{2} = 25 \times 10^{-6}\) - \((4.1 \times 10^{-2})^{2} = 16.81 \times 10^{-4}\) - \((7.3 \times 10^{-3})^{2} = 53.29 \times 10^{-6}\) ### Step 4: Combine the terms in the numerator and denominator Now, we can combine the terms: - Numerator: \[ 25 \times 10^{-4} + 16.81 \times 10^{-2} + 53.29 \times 10^{-4} = 25 \times 10^{-4} + 168.1 \times 10^{-4} + 53.29 \times 10^{-4} = 246.39 \times 10^{-4} \] - Denominator: \[ 25 \times 10^{-6} + 16.81 \times 10^{-4} + 53.29 \times 10^{-6} = 25 \times 10^{-6} + 168.1 \times 10^{-6} + 53.29 \times 10^{-6} = 246.39 \times 10^{-6} \] ### Step 5: Write the expression in simplified form Now we have: \[ \frac{246.39 \times 10^{-4}}{246.39 \times 10^{-6}} = \frac{246.39}{246.39} \times 10^{2} = 10^{2} = 100 \] ### Conclusion Thus, the value of the expression is \(100\).
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