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On simplification the value of 1-(1)/(1+...

On simplification the value of `1-(1)/(1+sqrt(2))+(1)/(1-sqrt(2))` is

A

`2sqrt(2)-1`

B

`1-2sqrt(2)`

C

`1-sqrt(2)`

D

`-2sqrt(2)`

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AI Generated Solution

The correct Answer is:
To simplify the expression \( 1 - \frac{1}{1+\sqrt{2}} + \frac{1}{1-\sqrt{2}} \), we will follow these steps: ### Step 1: Simplify \( \frac{1}{1+\sqrt{2}} \) To simplify \( \frac{1}{1+\sqrt{2}} \), we multiply the numerator and denominator by the conjugate of the denominator, which is \( 1-\sqrt{2} \): \[ \frac{1}{1+\sqrt{2}} \cdot \frac{1-\sqrt{2}}{1-\sqrt{2}} = \frac{1 - \sqrt{2}}{(1+\sqrt{2})(1-\sqrt{2})} \] Calculating the denominator: \[ (1+\sqrt{2})(1-\sqrt{2}) = 1^2 - (\sqrt{2})^2 = 1 - 2 = -1 \] Thus, we have: \[ \frac{1 - \sqrt{2}}{-1} = \sqrt{2} - 1 \] ### Step 2: Simplify \( \frac{1}{1-\sqrt{2}} \) Similarly, we simplify \( \frac{1}{1-\sqrt{2}} \) by multiplying by the conjugate \( 1+\sqrt{2} \): \[ \frac{1}{1-\sqrt{2}} \cdot \frac{1+\sqrt{2}}{1+\sqrt{2}} = \frac{1 + \sqrt{2}}{(1-\sqrt{2})(1+\sqrt{2})} \] Calculating the denominator: \[ (1-\sqrt{2})(1+\sqrt{2}) = 1^2 - (\sqrt{2})^2 = 1 - 2 = -1 \] Thus, we have: \[ \frac{1 + \sqrt{2}}{-1} = -1 - \sqrt{2} \] ### Step 3: Substitute back into the original expression Now we substitute back into the original expression: \[ 1 - \left(\sqrt{2} - 1\right) + \left(-1 - \sqrt{2}\right) \] This simplifies to: \[ 1 - \sqrt{2} + 1 - 1 - \sqrt{2} \] ### Step 4: Combine like terms Combining the terms gives us: \[ 1 + 1 - 1 - \sqrt{2} - \sqrt{2} = 1 - 2\sqrt{2} \] ### Final Result Thus, the simplified value of the expression \( 1 - \frac{1}{1+\sqrt{2}} + \frac{1}{1-\sqrt{2}} \) is: \[ \boxed{1 - 2\sqrt{2}} \]
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