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The harmonic mean of two numbers is 4. T...

The harmonic mean of two numbers is 4. Their arithmetic mean `A` and the geometric mean `G` satisfy the relation `2A+G^2=27.` Find two numbers.

A

6, 3

B

5, 4

C

5, -2.5

D

`-3, 1`

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Knowledge Check

  • The harmonic mean of two numbers is 4 and the arithmetic and geometric mean satisfy the relation 2A+G^2=27 the numbers are

    A
    6,3
    B
    5,4
    C
    5,-2.5
    D
    (-3,1)

  • The harmonic mean of two numbers is 4 and the arithmetic and geometric mean satisfy the relation 2A+G^2=27 the numbers are

    A
    6,3
    B
    5,4
    C
    5,-2.5
    D
    (-3,1)

  • The HM of two numbers is 4. If their arithmetic mean A and geometric mean G satisfy the relation 2A + G^(2) = 27 , then the numbers are

    A
    2, 6
    B
    3, 6
    C
    1, 3
    D
    1, 2

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    The harmonic mean of two positive numbers a and b is 4, their arithmetic mean is A and the geometric mean is G. If 2A+G^(2)=27, a+b=alpha and |a-b|=beta , then the value of (alpha)/(beta) is equal to

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