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Prove that tan[pi/4+1/2cos^(-1)""a/b]+ta...

Prove that `tan[pi/4+1/2cos^(-1)""a/b]+tan[pi/4-1/2cos^(-1)""a/b]=2b/a`

A

`a/(2b)`

B

`b/(2a)`

C

`(2b)/a`

D

`(2a)/b`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • tan[pi/4+1/2cos^(-1)(a/b)]+ tan[pi/4-1/2cos^(-1)(a/b)] is equal to

    A
    `(2a)/b`
    B
    `(2b)/a`
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    `a/b`
    D
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    A
    2a/b
    B
    2b/a
    C
    a/b
    D
    b/a

  • tan[pi/4+1/2cos^(-1)(a/b)]+tan[pi/4-1/2cos^(-1)(a/b)] is equal to

    A
    2a/b
    B
    2b/a
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