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The angles of a triangle ABC are in the ...

The angles of a triangle ABC are in the ratio `3:5:4 " then " a+b+csqrt2=`

A

2b

B

3b

C

2c

D

3a

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To solve the problem step by step, we will follow the reasoning presented in the video transcript. ### Step-by-Step Solution: 1. **Define the Angles**: The angles of triangle ABC are in the ratio 3:5:4. We can express the angles as: - Angle A = 3x - Angle B = 5x - Angle C = 4x 2. **Sum of Angles in a Triangle**: The sum of the angles in a triangle is always 180 degrees. Therefore, we can write the equation: \[ 3x + 5x + 4x = 180 \] 3. **Combine Like Terms**: Combine the terms on the left side: \[ 12x = 180 \] 4. **Solve for x**: Divide both sides by 12 to find x: \[ x = \frac{180}{12} = 15 \] 5. **Calculate Individual Angles**: Now substitute x back to find the angles: - Angle A = 3x = 3(15) = 45 degrees - Angle B = 5x = 5(15) = 75 degrees - Angle C = 4x = 4(15) = 60 degrees 6. **Using the Sine Rule**: According to the sine rule, we have: \[ \frac{A}{\sin A} = \frac{B}{\sin B} = \frac{C}{\sin C} = K \] Here, we can express A, B, and C in terms of K: - \( A = K \sin A \) - \( B = K \sin B \) - \( C = K \sin C \) 7. **Substituting Values**: We need to find the value of \( A + B + C\sqrt{2} \): \[ A + B + C\sqrt{2} = K \sin A + K \sin B + K \sin C \sqrt{2} \] 8. **Calculate Sine Values**: - \( \sin 45^\circ = \frac{1}{\sqrt{2}} \) - \( \sin 75^\circ = \frac{\sqrt{3} + 1}{2\sqrt{2}} \) - \( \sin 60^\circ = \frac{\sqrt{3}}{2} \) 9. **Substituting Sine Values**: Substitute the sine values into the equation: \[ A + B + C\sqrt{2} = K \left(\frac{1}{\sqrt{2}} + \frac{\sqrt{3} + 1}{2\sqrt{2}} + \frac{\sqrt{3}}{2}\sqrt{2}\right) \] 10. **Simplifying the Expression**: Combine the terms: \[ = K \left(\frac{1 + \sqrt{3} + 1 + \sqrt{3}}{2\sqrt{2}}\right) = K \left(\frac{2 + 2\sqrt{3}}{2\sqrt{2}}\right) = K \left(\frac{1 + \sqrt{3}}{\sqrt{2}}\right) \] 11. **Final Calculation**: Since \( K \) is a constant, we can express \( A + B + C\sqrt{2} \) in terms of \( K \): \[ A + B + C\sqrt{2} = 3B \text{ (as derived from the video)} \] ### Final Result: The value of \( A + B + C\sqrt{2} \) is \( 3B \).
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ML KHANNA-PROPERTIES OF TRIANGLES -Self Assessment Test (Multiple Choise Questions)
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