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f and g are two differentiable functions which satisfy the condition ` g'(a) = 2,g (a) =b and (f og) =I` identity function , then f'(b) is equal to

A

`2/3`

B

`1/2`

C

`2`

D

None

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The correct Answer is:
To solve the problem, we need to find \( f'(b) \) given the conditions provided. Let's break it down step by step. ### Step 1: Understand the Identity Function The identity function is defined as \( I(x) = x \). This means that for any input \( x \), the output is the same, i.e., \( f(g(x)) = x \). ### Step 2: Differentiate the Identity Function Since \( f(g(x)) = x \), we can differentiate both sides with respect to \( x \): \[ \frac{d}{dx}[f(g(x))] = \frac{d}{dx}[x] \] Using the chain rule on the left side, we have: \[ f'(g(x)) \cdot g'(x) = 1 \] ### Step 3: Substitute the Given Values We know from the problem statement: - \( g'(a) = 2 \) - \( g(a) = b \) Now, we can substitute \( x = a \) into our differentiated equation: \[ f'(g(a)) \cdot g'(a) = 1 \] Substituting \( g(a) = b \) and \( g'(a) = 2 \): \[ f'(b) \cdot 2 = 1 \] ### Step 4: Solve for \( f'(b) \) Now, we can solve for \( f'(b) \): \[ f'(b) = \frac{1}{2} \] ### Final Answer Thus, \( f'(b) = \frac{1}{2} \). ---
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