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Let h(x) = f (x) -(f (x))^2+ (f (x))^3 f...

Let `h(x) = f (x) -(f (x))^2+ (f (x))^3` for every real number x: Then

A

h is increasing whenever f is increasing

B

h is increasing whenever f is decreasing

C

h is decreasing whenever f is decreasing

D

nothing can be said in general.

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To solve the problem, we need to analyze the function \( h(x) = f(x) - (f(x))^2 + (f(x))^3 \) and determine when it is increasing or decreasing. We will do this by finding the derivative \( h'(x) \) and analyzing its sign. ### Step 1: Differentiate \( h(x) \) We start by differentiating \( h(x) \): \[ h'(x) = \frac{d}{dx}[f(x)] - \frac{d}{dx}[(f(x))^2] + \frac{d}{dx}[(f(x))^3] \] Using the chain rule, we differentiate each term: - The derivative of \( f(x) \) is \( f'(x) \). - The derivative of \( (f(x))^2 \) is \( 2f(x)f'(x) \). - The derivative of \( (f(x))^3 \) is \( 3(f(x))^2f'(x) \). Putting it all together, we have: \[ h'(x) = f'(x) - 2f(x)f'(x) + 3(f(x))^2f'(x) \] ### Step 2: Factor out \( f'(x) \) Next, we can factor \( f'(x) \) out of the expression: \[ h'(x) = f'(x) \left( 1 - 2f(x) + 3(f(x))^2 \right) \] ### Step 3: Analyze the quadratic expression Let \( y = f(x) \). Then we can rewrite the expression in the parentheses: \[ 1 - 2y + 3y^2 \] This is a quadratic equation in \( y \). To analyze its sign, we can complete the square or find its roots. ### Step 4: Finding the roots The roots of the quadratic \( 3y^2 - 2y + 1 = 0 \) can be found using the quadratic formula: \[ y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{2 \pm \sqrt{(-2)^2 - 4 \cdot 3 \cdot 1}}{2 \cdot 3} = \frac{2 \pm \sqrt{4 - 12}}{6} = \frac{2 \pm \sqrt{-8}}{6} \] Since the discriminant is negative, the quadratic has no real roots and is always positive (as the coefficient of \( y^2 \) is positive). ### Step 5: Conclusion about \( h'(x) \) Since \( 1 - 2f(x) + 3(f(x))^2 > 0 \) for all real \( f(x) \), the sign of \( h'(x) \) depends solely on \( f'(x) \): - If \( f'(x) > 0 \), then \( h'(x) > 0 \) (i.e., \( h(x) \) is increasing). - If \( f'(x) < 0 \), then \( h'(x) < 0 \) (i.e., \( h(x) \) is decreasing). ### Step 6: Final Result Thus, we conclude: - \( h(x) \) is increasing when \( f(x) \) is increasing. - \( h(x) \) is decreasing when \( f(x) \) is decreasing.
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