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Assertion : Ethanol is the first member ...

Assertion : Ethanol is the first member of the alcohol homologous series.
Reason : A homologous series cannot be represented by a general formula.

A

If both assertion and reason are true and reason is the correct explanation of assertion

B

If both assertion and reason are true but reason is not the correct explanation of assertion

C

If assertion is true but reason is false

D

If both assertion and reason are false.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the assertion and reason question, we need to analyze both the assertion and the reason separately. ### Step 1: Analyze the Assertion The assertion states that "Ethanol is the first member of the alcohol homologous series." - **Correct Information**: The first member of the alcohol homologous series is actually methanol (CH₃OH), not ethanol (C₂H₅OH). - **Conclusion**: Therefore, the assertion is **false**. ### Step 2: Analyze the Reason The reason states that "A homologous series cannot be represented by a general formula." - **Correct Information**: A homologous series can indeed be represented by a general formula. For example, the general formula for alcohols is CₙH₂ₙ₊₁OH, where 'n' is the number of carbon atoms. This shows that the series follows a specific pattern. - **Conclusion**: Therefore, the reason is also **false**. ### Step 3: Final Conclusion Since both the assertion and the reason are false, we can conclude that the correct answer to the question is option D: Both assertion and reason are false. ### Summary of the Solution - Assertion: False (Methanol is the first member, not Ethanol). - Reason: False (Homologous series can be represented by a general formula). - Final Answer: Both assertion and reason are false (Option D).

To solve the assertion and reason question, we need to analyze both the assertion and the reason separately. ### Step 1: Analyze the Assertion The assertion states that "Ethanol is the first member of the alcohol homologous series." - **Correct Information**: The first member of the alcohol homologous series is actually methanol (CH₃OH), not ethanol (C₂H₅OH). - **Conclusion**: Therefore, the assertion is **false**. ...
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