Home
Class 8
PHYSICS
A particle is moving in a circle of radi...

A particle is moving in a circle of radius 2 m. Show the following position of the particle.
2 m from the centre towards south.

Text Solution

AI Generated Solution

To solve the problem of showing the position of a particle moving in a circle of radius 2 meters, specifically when it is 2 meters from the center towards the south, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Circle**: - A circle is defined by its center and radius. In this case, the radius is given as 2 meters. 2. **Draw the Circle**: ...
Promotional Banner

Topper's Solved these Questions

  • MEASUREMENTS AND MOTION

    MTG IIT JEE FOUNDATION|Exercise EXERCISE(MCQ)|46 Videos

  • MEASUREMENTS AND MOTION

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (MATCH THE FOLLOWING)|3 Videos

  • MEASUREMENTS AND MOTION

    MTG IIT JEE FOUNDATION|Exercise EXERCISE(INTEGER/ NUMERICAL VALUE TYPE )|5 Videos

  • MAGNETIC EFFECTS OF ELECTRIC CURRENT

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (INTEGER / NUMERICAL VALUE TYPE)|3 Videos

  • SOME NATURAL PHENOMENA

    MTG IIT JEE FOUNDATION|Exercise Olympaid/HOTS Corner |10 Videos

Similar Questions

Explore conceptually related problems

A particle is moving in a circle of radius 1 m with speed varying with time as v = (2t) m/s. In first 2 sec:

A particle is moving in a circle of radius 1 m with speed varying with time as v=(2t)m//s . In first 2 s

A particle moves in a circle of radius 25 cm at two revolutions per sec. The acceleration of the particle in m//s^(2) is:

A particle of mass m is moving in a circle of radius r. The centripetal acceleration (a_(c)) of the particle varies with the time according to the relation, a_(c)=Kt^(2) , where K is a positive constant and t is the time. The magnitude of the time rate of change of angular momentum of the particle about the centre of the circle is

A particle moves in a circle of radius 4m with a linear speed of 20m//s . Find the angular speed.

A particle of mass 200 g is moving in a circle of radius 2 m. The particle is just looping the loop. The speed of the particle and the tension in the string at highest point of the circule path are (g=10ms^(-2))

A particle is moving along a circle of radius 20cm , with a linear velocity of 2m//s. Calculate the angular velocity of the particle.

Centripetal acceleration of a particle of mass m moving in a circle of radius r is 4//r^(2) . What is the angular momentum of the particle ?

If a particle is moving along a circle of radius 3 m with a constant speed 9 m//s , then it covers a quarter of the circle in time of