Calculate the pressure of `CO _(2) ` gas at 700 K in the heterogeneous equilibrium reaction `Ca CO _(3) (s) hArr CaO (s) + 2 CO _(2) (g) if Delta G ^(@)` for the reaction is `130.2 kJ mol ^(-1).`

Explanation

Here, `K_(p) = P_(CO_(2)).Delta G^(@) = -RT ln K_(p)`
In `K_(p) = -(Delta G^(@))/(RT) = -(130.2 xx 10^(3) J mol^(-1))/((8.314 J K^(-1) mol^(-1)) (700K)) rArr P_(CO_(2)) = K_(P) = 5.178 xx 10^(-9)` atm