The value of `Delta G ^(@)`for the phosphorylation of glucose in glycolysis is `13.8` kJ/mol. Find the value of `K _(c)` at 298 K.

Explanation

Given : `Delta G^(@) = 13.8 k J mol^(-1) = 13.8 xx 10^(3) J mol^(-1)`
`Delta G^(@) - RT ln K_(c) rArr ln K_(c) = -13.8 xx 10^(3) J mol^(-1)//(8.314 J mol^(-1)K^(-) xx 298 K)`
In `K_(c ) = -5.569 rArr K_(c )= e^(-5.569) rArr K_(c ) = 3.81 xx 10^(-3)`