Home
Class 14
MATHS
On March 1st 2016, Sherry saved 1. Every...

On March 1st 2016, Sherry saved 1. Everyday starting from March 2nd 2016, he save 1 more than the previous day. Find the first date after March 1st 2016 at the end of which his total savings will be a perfect square.

A

A)17th March 2016

B

B)18th April 2016

C

C)26th March 2016

D

D)None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to determine the total savings of Sherry over a series of days and find the first date after March 1st, 2016, when the total savings will be a perfect square. ### Step 1: Understand the savings pattern Sherry saves 1 rupee on March 1st, 2016. Starting from March 2nd, he saves 1 rupee more than the previous day. This means: - On March 1st: 1 rupee - On March 2nd: 2 rupees - On March 3rd: 3 rupees - On March 4th: 4 rupees - ... - On March n: n rupees ### Step 2: Calculate total savings after n days The total savings after n days can be calculated using the formula for the sum of the first n natural numbers: \[ S_n = 1 + 2 + 3 + ... + n = \frac{n(n + 1)}{2} \] ### Step 3: Identify the first perfect square We need to find the smallest value of n such that \( S_n \) is a perfect square. This means we need to check values of n starting from 1 and see if \( \frac{n(n + 1)}{2} \) is a perfect square. ### Step 4: Check values of n 1. For \( n = 1 \): \[ S_1 = \frac{1(1 + 1)}{2} = 1 \quad (\text{Perfect square: } 1^2) \] Date: March 1, 2016 2. For \( n = 2 \): \[ S_2 = \frac{2(2 + 1)}{2} = 3 \quad (\text{Not a perfect square}) \] 3. For \( n = 3 \): \[ S_3 = \frac{3(3 + 1)}{2} = 6 \quad (\text{Not a perfect square}) \] 4. For \( n = 4 \): \[ S_4 = \frac{4(4 + 1)}{2} = 10 \quad (\text{Not a perfect square}) \] 5. For \( n = 5 \): \[ S_5 = \frac{5(5 + 1)}{2} = 15 \quad (\text{Not a perfect square}) \] 6. For \( n = 6 \): \[ S_6 = \frac{6(6 + 1)}{2} = 21 \quad (\text{Not a perfect square}) \] 7. For \( n = 7 \): \[ S_7 = \frac{7(7 + 1)}{2} = 28 \quad (\text{Not a perfect square}) \] 8. For \( n = 8 \): \[ S_8 = \frac{8(8 + 1)}{2} = 36 \quad (\text{Perfect square: } 6^2) \] Date: March 8, 2016 ### Conclusion The first date after March 1st, 2016, at the end of which Sherry's total savings will be a perfect square is **March 8, 2016**.
Promotional Banner

Topper's Solved these Questions

  • PROGRESSIONS

    DISHA PUBLICATION|Exercise STANDARD LEVEL|27 Videos
  • PROGRESSIONS

    DISHA PUBLICATION|Exercise EXPERT LEVEL|25 Videos
  • PROGRESSIONS

    DISHA PUBLICATION|Exercise TEST YOURSELF|15 Videos
  • PROFIT, LOSS AND DISCOUNT

    DISHA PUBLICATION|Exercise Test Yourself|15 Videos
  • QUADRATIC AND CUBIC EQUATIONS

    DISHA PUBLICATION|Exercise Test Yourself |15 Videos

Similar Questions

Explore conceptually related problems

Receipt and Payment Account of Maitrey Sports Club showed that Rs. 68,500 were received by way of subscriptions for the year ended on March 31, 2017. The additional information was as under: 1. Subscription Outstanding as on March 31, 2016 were Rs. 6,500. 2. Subscription received in advance as on March 31, 2016 were Rs. 4,100, 3. Subscription Outstanding as on March 31, 2017 were Rs. 5,400 4. Subscription received in advance as on March 31, 2017 were Rs. 2,500. Show how that above information would appear in the final accounts for the year ended on March 31, 2017 of Maitrey Sports Club.

On 1st Jan 2016 , Sanika decides to save Rs10 , Rs11 on second day , Rs12 on third day. If she decide to save like this, then on 31^(st) Dec 2016 What would be her total saving?

On 1st Jan 2018, Sanikadecides to save Rupees 10,Rupees 11 on the second day, Rupees 12 on the third day . She decides to save like this . What would be her total savings at the end of the year ?

The third day before 1st January 2019 was Saturday . Which day will the fourth day of March 2020 be ?

On 1st February 2016, Raj Ltd. received in advance the first call of Rs. 25 per share on 400 equity shares. The first casll was due on 31st March 2016. Journalise the above transactions.

From the following information determine the amount to be debited to Stationery Account in Income and Expenditure Account for the year ended 31st March 2019 : {:(,,Rs),("Stock stationery on 1st April 2018",,"30,000"),("Creditors for stationery on 1st April 2018",,"20,000"),("Amount paid for stationery during the year ended 31st March 2019",,"1,08,000"),("Stock of stationery on 31st March 2019",,"5,000"),("Creditors for stationery on 31st March 2019",,"13,000"):} Also show the above items in the Income and Expenditure Account for the year ended 31st March 2019 and in the Balance Sheet as at that date.

A partner draws Rs.2,000 each on 1st April 2018, 1st July 2018, 1st October, 2018 and 1st Jaunary 2019. For the year ended 31st March, 2019 interest on drawings @8% per annum will be :

A and B are partners in a firm sharing profits and losses in the ratio of 2 : 1. They decide to take C into partnership for 1/5th share on 1st April 2017. For this purpose goodwill is to be valued at 80% of the average annual profits of the previous three or four years, whichever is higher. The average profits for the last four years are : {:(,," Rs."),("Year ending on 31st March 2014",,"98,000"),("Year ending on 31st March 2015",,"80,000"),("Year ending on 31st March 2016",,"76,000"),("Year ending on 31st March 2017",,"1,20,000"):} Calculate the value of Goodwill.

DISHA PUBLICATION-PROGRESSIONS-FOUNDATION LEVEL
  1. (11^2 + 12^2 + 13^2 + …+ 20^2) = ?

    Text Solution

    |

  2. A sequence is generated by the rule that the xth is x^2+1 for each pos...

    Text Solution

    |

  3. On March 1st 2016, Sherry saved 1. Everyday starting from March 2nd 20...

    Text Solution

    |

  4. A man arranges to pay off a debt of 3,600 in 40 annual instalments wh...

    Text Solution

    |

  5. A number 15 is divided into three parts which are in AP and the sum of...

    Text Solution

    |

  6. A boy agrees to work at the rate of one rupee on the first day, two ru...

    Text Solution

    |

  7. What is the sum of all the two-digit numbers which when divided by 7 g...

    Text Solution

    |

  8. IF 1+10+10^2+…….upto n terms =(10^n-1)/9 then the sum of the series 4+...

    Text Solution

    |

  9. A man starts going for morning walk every day. The distance walked by ...

    Text Solution

    |

  10. If sixth term of a H. P. is 1/61 and its tenth term is 1/105 then the...

    Text Solution

    |

  11. The sum of the 6th and 15th elements of an arithmetic progression is e...

    Text Solution

    |

  12. In a geometric progression, the sum of the first and the last term is ...

    Text Solution

    |

  13. Four geometric means are inserted between 1/8 and 128. Find the third ...

    Text Solution

    |

  14. How many terms of the series 1 + 3 + 5 + 7 + ..... amount to 123454321...

    Text Solution

    |

  15. An equilateral triangle is drawn by joining the midpoints of the sides...

    Text Solution

    |

  16. The sum to infinity of the progression 9-3 + 1-1/3 + ……..is

    Text Solution

    |

  17. The sequence [xn] is a GP with x2/x4 = 1/4 and x1 + x4 = 108. What wil...

    Text Solution

    |

  18. The 1st, 8th and 22nd terms of an AP are three conscutive terms of a G...

    Text Solution

    |

  19. If the mth term of an AP is 1/n and nth term is 1/m, then find the sum...

    Text Solution

    |

  20. Find the value of 1– 2 – 3 + 2 – 3 – 4 + ... + upto 100 terms.

    Text Solution

    |