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IF 1^3+2^3+…….+9^3=2025 then the value o...

IF `1^3+2^3+…….+9^3=2025` then the value of `(0.11)^3 +(0.22)^3+……+(0.99)^3` is close to

A

0.2695

B

0.3695

C

2.695

D

3.695

Text Solution

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The correct Answer is:
C
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If 1^3+2^3+ dot +9^3=2025 , then the value of (0. 11)^3+(0. 22)^3+ dot+(0. 99)^3 is close to (a) 0.2695 (b) 0.3695 (c) 2.695 (d) 3.695

If 1^(3) + 2^(3) +……. + 9^(3) =2025, then the approximate value of (0.11)^(3)+(0.22)^(3) +…..+ (0.99)^(3) is

Evaluate: (0.2)^(3)-(0.3)^(3)+(0.1)^(3)

Value of ( 1^0 + 2^0 + 3^0 ) is

Value of ( 9^0 + 1/ 5^0 )^3 is

the value of 1.1!+ 2.2!+ 3.3!+ ....+ n.n!

If A =((0.1)^3+(0.2)^3+(0.3)^3+3(0.005 + 0.016 + 0.027) + 0.036)/((0.1)^2+(0.2)^2+ (0.3)^2+0.04 + 0.06 + 0.12) ,then the value of 60A is: यदि A =((0.1)^3+(0.2)^3+(0.3)^3+3(0.005 + 0.016 + 0.027) + 0.036)/((0.1)^2+(0.2)^2+ (0.3)^2+0.04 + 0.06 + 0.12) है, तो 60A का मान क्या होगा ?

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