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The line y = 0 divides the line joining ...

The line y = 0 divides the line joining the points (3, -5) and (- 4, 7) in the ratio
(a)`3 : 4`
(b)`4 : 5`
(c)`5 : 7`
(d)`7 : 9`

A

`3 : 4`

B

`4 : 5`

C

`5 : 7`

D

`7 : 9`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio in which the line \( y = 0 \) divides the line segment joining the points \( (3, -5) \) and \( (-4, 7) \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Points**: We have two points: - Point 1: \( (x_1, y_1) = (3, -5) \) - Point 2: \( (x_2, y_2) = (-4, 7) \) 2. **Use the Section Formula**: The section formula states that if a line segment joining two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is divided by a point \( P(x, y) \) in the ratio \( m:n \), then: \[ y = \frac{m \cdot y_2 + n \cdot y_1}{m + n} \] In our case, we want to find the ratio \( m:n \) such that \( y = 0 \). 3. **Set Up the Equation**: Let’s assume the ratio in which the line divides the segment is \( k:1 \) (where \( k \) is the unknown we need to find). Thus, we can write: \[ 0 = \frac{k \cdot y_2 + 1 \cdot y_1}{k + 1} \] Substituting \( y_1 = -5 \) and \( y_2 = 7 \): \[ 0 = \frac{k \cdot 7 + 1 \cdot (-5)}{k + 1} \] 4. **Simplify the Equation**: This simplifies to: \[ 0 = \frac{7k - 5}{k + 1} \] For this fraction to be zero, the numerator must be zero: \[ 7k - 5 = 0 \] 5. **Solve for \( k \)**: Rearranging gives: \[ 7k = 5 \implies k = \frac{5}{7} \] 6. **Determine the Ratio**: The ratio \( m:n \) is \( k:1 \), which translates to: \[ \frac{5}{7} : 1 \] This can be expressed as: \[ 5 : 7 \] ### Conclusion: The line \( y = 0 \) divides the line segment joining the points \( (3, -5) \) and \( (-4, 7) \) in the ratio \( 5:7 \). Therefore, the correct option is **(c) 5 : 7**.
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