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For what value of k, the equations 3x -...

For what value of k, the equations 3x - y = 8 and 9x - ky = 24 will have infinitely many solutions ?
(a)6
(b)5
(c)3
(d)1

A

6

B

5

C

3

D

1

Text Solution

AI Generated Solution

The correct Answer is:
To determine the value of \( k \) for which the equations \( 3x - y = 8 \) and \( 9x - ky = 24 \) have infinitely many solutions, we can follow these steps: ### Step 1: Write the equations in standard form The given equations are: 1. \( 3x - y = 8 \) 2. \( 9x - ky = 24 \) We can rewrite these equations in the form \( Ax + By + C = 0 \): 1. \( 3x - y - 8 = 0 \) (Here, \( A_1 = 3, B_1 = -1, C_1 = -8 \)) 2. \( 9x - ky - 24 = 0 \) (Here, \( A_2 = 9, B_2 = -k, C_2 = -24 \)) ### Step 2: Apply the condition for infinitely many solutions For the two equations to have infinitely many solutions, the ratios of the coefficients must be equal: \[ \frac{A_1}{A_2} = \frac{B_1}{B_2} = \frac{C_1}{C_2} \] ### Step 3: Set up the equations using the ratios Using the first two ratios: \[ \frac{3}{9} = \frac{-1}{-k} \] ### Step 4: Simplify the ratios Simplifying the left side: \[ \frac{3}{9} = \frac{1}{3} \] So we have: \[ \frac{1}{3} = \frac{1}{k} \] ### Step 5: Cross-multiply to solve for \( k \) Cross-multiplying gives: \[ 1 \cdot k = 3 \cdot 1 \] Thus: \[ k = 3 \] ### Conclusion The value of \( k \) for which the equations have infinitely many solutions is \( \boxed{3} \). ---
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