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The number of words that can be formed o...

The number of words that can be formed out of the letters of the word COMMITTEE is

A

`(9!)/((2!)^3)`

B

`(9!)/((2!)^2)`

C

`(9!)/(2!)`

D

`9!`

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of distinct words that can be formed from the letters of the word "COMMITTEE", we will follow these steps: ### Step 1: Count the total number of letters The word "COMMITTEE" consists of 9 letters. ### Step 2: Identify the frequency of each letter In the word "COMMITTEE", the frequency of each letter is as follows: - C: 1 - O: 1 - M: 2 - I: 1 - T: 2 - E: 2 ### Step 3: Use the formula for permutations of multiset The formula to find the number of distinct permutations of letters in a word is given by: \[ \text{Number of permutations} = \frac{n!}{p_1! \times p_2! \times p_3! \times \ldots} \] where \( n \) is the total number of letters, and \( p_1, p_2, p_3, \ldots \) are the frequencies of the repeated letters. ### Step 4: Substitute the values into the formula Here, \( n = 9 \) (total letters), and the repeated letters are: - M: 2 times - T: 2 times - E: 2 times Thus, we have: \[ \text{Number of permutations} = \frac{9!}{2! \times 2! \times 2!} \] ### Step 5: Calculate the factorials Now we calculate \( 9! \) and \( 2! \): \[ 9! = 362880 \] \[ 2! = 2 \] ### Step 6: Substitute the factorial values into the equation Now substituting back into the equation: \[ \text{Number of permutations} = \frac{362880}{2 \times 2 \times 2} = \frac{362880}{8} \] ### Step 7: Perform the division Now, we calculate: \[ \frac{362880}{8} = 45360 \] ### Conclusion The total number of distinct words that can be formed from the letters of the word "COMMITTEE" is **45360**. ---
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