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Find the number of ways in which 8064 ca...

Find the number of ways in which 8064 can be resolved as the product of two factors?

A

20

B

21

C

22

D

24

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The correct Answer is:
To find the number of ways in which 8064 can be resolved as the product of two factors, we will follow these steps: ### Step 1: Prime Factorization of 8064 First, we need to factor 8064 into its prime factors. - Start by dividing 8064 by 2 (the smallest prime number): - 8064 ÷ 2 = 4032 - 4032 ÷ 2 = 2016 - 2016 ÷ 2 = 1008 - 1008 ÷ 2 = 504 - 504 ÷ 2 = 252 - 252 ÷ 2 = 126 - 126 ÷ 2 = 63 - Now, 63 is not divisible by 2, so we divide by the next prime number, which is 3: - 63 ÷ 3 = 21 - 21 ÷ 3 = 7 - Finally, 7 is a prime number. Thus, the prime factorization of 8064 is: \[ 8064 = 2^7 \times 3^2 \times 7^1 \] ### Step 2: Finding Total Number of Factors To find the total number of factors of a number given its prime factorization \( p^a \times q^b \times r^c \), the formula is: \[ (a+1)(b+1)(c+1) \] For 8064: - \( a = 7 \) (for \( 2^7 \)) - \( b = 2 \) (for \( 3^2 \)) - \( c = 1 \) (for \( 7^1 \)) Calculating the total number of factors: \[ (7+1)(2+1)(1+1) = 8 \times 3 \times 2 \] Now, calculate: \[ 8 \times 3 = 24 \] \[ 24 \times 2 = 48 \] So, 8064 has a total of 48 factors. ### Step 3: Resolving into Products of Two Factors To find the number of ways to express 8064 as a product of two factors, we need to consider that each pair of factors \( (a, b) \) such that \( a \times b = 8064 \) can be counted once. Since each factorization \( (a, b) \) is the same as \( (b, a) \), we divide the total number of factors by 2: \[ \text{Number of ways} = \frac{\text{Total Factors}}{2} = \frac{48}{2} = 24 \] ### Final Answer Thus, the number of ways in which 8064 can be resolved as the product of two factors is **24**. ---
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