Home
Class 14
MATHS
There are 20 people among whom two are s...

There are 20 people among whom two are sisters. Find the number of ways in which we can arrange them around a circle so that there is exactly one person between the two sisters.

A

18!

B

2!18!

C

19!

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of arranging 20 people around a circle such that exactly one person is between two sisters, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Total People**: We have 20 people in total, out of which 2 are sisters. 2. **Fix the Circle**: When arranging people in a circle, we can fix one person to eliminate the circular permutations. Thus, we can think of arranging the remaining people around this fixed point. 3. **Consider the Arrangement of Other People**: If we take out the two sisters, we are left with 18 other people. We can arrange these 18 people in a circle. The number of ways to arrange \( n \) people in a circle is given by \( (n-1)! \). Therefore, the number of ways to arrange 18 people in a circle is: \[ 17! \text{ (since } 18 - 1 = 17\text{)} \] 4. **Positioning the Sisters**: We need to place the two sisters such that there is exactly one person between them. When we arrange the 18 people, there will be 18 gaps created between them (including the gap before the first person and after the last person). 5. **Choosing the Gaps**: We can choose any one of these 18 gaps to place the first sister. The second sister must then go into the gap that is two positions away from the first sister (to ensure there is one person between them). 6. **Arranging the Sisters**: The two sisters can be arranged in the chosen gaps in 2 different ways (Sister A in gap 1 and Sister B in gap 2, or Sister B in gap 1 and Sister A in gap 2). This gives us: \[ 2! = 2 \text{ ways} \] 7. **Final Calculation**: Now, we combine the arrangements of the 18 people and the arrangements of the sisters: \[ \text{Total arrangements} = 17! \times 18 \times 2 \] Here, \( 18 \) is the number of ways to choose the gap for the first sister. 8. **Simplifying the Expression**: Thus, the total number of arrangements can be expressed as: \[ 2 \times 18 \times 17! = 36 \times 17! \] ### Conclusion: The total number of ways to arrange the 20 people around a circle such that there is exactly one person between the two sisters is: \[ 36 \times 17! \]
Promotional Banner

Topper's Solved these Questions

  • PERMUTATIONS AND COMBINATIONS

    DISHA PUBLICATION|Exercise PRACTICE EXERCISES ( STANDARD LEVEL)|82 Videos
  • PERMUTATIONS AND COMBINATIONS

    DISHA PUBLICATION|Exercise PRACTICE EXERCISES ( EXPERT LEVEL )|48 Videos
  • PERMUTATIONS AND COMBINATIONS

    DISHA PUBLICATION|Exercise TEST YOURSELF|15 Videos
  • PERCENTAGES

    DISHA PUBLICATION|Exercise PRACTICE EXERCISE (TEST YOURSELF)|15 Videos
  • PROBABILITY

    DISHA PUBLICATION|Exercise TEST YOURSELF|15 Videos

Similar Questions

Explore conceptually related problems

There are 20 persons among whom are two brothers. The number of ways in which we can arrange them around a circle so that there is exactly one person between the two brothers, is

There are fifty persons among whom 2 are brothers. The number of ways they can be arranged in a circle, if there is exactly one person between the two brothers, is

The number of ways of arranging 7 persons around a circle is

The number of ways of arranging 9persons around a circle if there are two other persons between two particular persons is:

Find the number of ways in which 5 boys and 3 girls can be arranged in a row so that no two girls are together.

Find the number of ways in which 10 persons can sit round a circular table so that none of them has the same neighbours in any two arrangements.

The number of ways in which seven persons can be arranged at a round table if two particular persons may not sit together, is

DISHA PUBLICATION-PERMUTATIONS AND COMBINATIONS-PRACTICE EXERCISES ( FOUNDATION LEVEL)
  1. There are 6 boxes numbered 1, 2, ... 6. Each box is to be filled up ei...

    Text Solution

    |

  2. In how many ways five chocolates can be chosen from an unlimited numbe...

    Text Solution

    |

  3. There are 20 people among whom two are sisters. Find the number of way...

    Text Solution

    |

  4. In a company, each employee gives a gift to every other employee. If t...

    Text Solution

    |

  5. In how many ways can Ram choose a vowel and a constant from the letter...

    Text Solution

    |

  6. There are three rooms in a hotel: one single, one double and one for f...

    Text Solution

    |

  7. The digits, from 0 to 9 are written on 10 slips of paper (one digit on...

    Text Solution

    |

  8. The number of ways in which 7 different books can be given to 5 studen...

    Text Solution

    |

  9. In how many ways can 13 different alphabets (a, b, c, ... m) be arrang...

    Text Solution

    |

  10. Number of ways in which the letters of word GARDEN can be arranged wit...

    Text Solution

    |

  11. In how many ways can a mixed double game can be arranged from amongst ...

    Text Solution

    |

  12. In how many ways can 21 identical white balls and 19 identical black b...

    Text Solution

    |

  13. If 5 parallel straight lines are intersected by 4 parallel straight, t...

    Text Solution

    |

  14. The number of ways in which a couple can sit around a table with 6 gue...

    Text Solution

    |

  15. How many different words beginning with O and ending with E can be for...

    Text Solution

    |

  16. How many 6 digit number can be formed from the digits 1, 2, 3, 4, 5, 6...

    Text Solution

    |

  17. There are 5 candidates in an election and 3 of them are to be elected....

    Text Solution

    |

  18. If ""^(2n+1)P(n-1) : ""^(2n-1)P(n) =3 :5 the possible value of n will ...

    Text Solution

    |

  19. All possible two factors products are formed from the numbers 1, 2, 3,...

    Text Solution

    |

  20. A set of 15 different words are given. In how many ways is it possible...

    Text Solution

    |