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Seven nouns, five verbs, and two adjecti...

Seven nouns, five verbs, and two adjectives are written on a blackboard. We can form a sentence by choosing one word of each type, and we do not care about how much sense the sentence makes. How many ways are there to do this?

A

`7^2 xx 5^2 xx 2^2`

B

`7^1 xx 5^1 xx 2^1 xx 3!`

C

`7! xx 5! xx 2 !`

D

`2^7 xx 2^5 xx 2^2`

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AI Generated Solution

The correct Answer is:
To solve the problem of how many ways we can form a sentence using one noun, one verb, and one adjective from the given words, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the number of words available**: - We have 7 nouns, 5 verbs, and 2 adjectives. 2. **Choose one word from each category**: - For nouns, we can choose 1 out of 7: **7 ways**. - For verbs, we can choose 1 out of 5: **5 ways**. - For adjectives, we can choose 1 out of 2: **2 ways**. 3. **Calculate the total combinations**: - The total number of ways to choose one word from each category is the product of the number of choices: \[ \text{Total combinations} = \text{Number of nouns} \times \text{Number of verbs} \times \text{Number of adjectives} \] \[ = 7 \times 5 \times 2 \] 4. **Perform the multiplication**: - First, calculate \(7 \times 5 = 35\). - Then multiply \(35 \times 2 = 70\). - So, there are **70 ways** to choose one noun, one verb, and one adjective. 5. **Consider the arrangement of the chosen words**: - Since the order of the words matters in a sentence, we can arrange the three chosen words (noun, verb, adjective) in different ways. The number of arrangements of 3 words is given by \(3!\) (3 factorial). - Calculate \(3! = 3 \times 2 \times 1 = 6\). 6. **Calculate the final total**: - Multiply the number of combinations by the number of arrangements: \[ \text{Final total} = \text{Total combinations} \times \text{Arrangements} \] \[ = 70 \times 6 = 420 \] ### Final Answer: Thus, the total number of ways to form a sentence is **420**. ---
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