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The number of circles that can be drawn ...

The number of circles that can be drawn out of 10 points of which 7 are collinear is

A

130

B

85

C

45

D

Cannot be determined

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AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of circles that can be drawn from 10 points, where 7 points are collinear, we can follow these steps: ### Step 1: Understand the requirement to form a circle A unique circle can be formed by selecting any three non-collinear points. Since we have 7 collinear points, we cannot select all three points from these collinear points. ### Step 2: Identify the points We have: - 7 collinear points (let's call them A1, A2, A3, A4, A5, A6, A7) - 3 non-collinear points (let's call them B1, B2, B3) ### Step 3: Calculate the different combinations to form circles We can form circles in the following ways: 1. **Select 1 point from the collinear points and 2 points from the non-collinear points**: - The number of ways to select 1 point from 7 collinear points: \( \binom{7}{1} = 7 \) - The number of ways to select 2 points from 3 non-collinear points: \( \binom{3}{2} = 3 \) - Total combinations for this case: \( 7 \times 3 = 21 \) 2. **Select 2 points from the collinear points and 1 point from the non-collinear points**: - The number of ways to select 2 points from 7 collinear points: \( \binom{7}{2} = \frac{7 \times 6}{2 \times 1} = 21 \) - The number of ways to select 1 point from 3 non-collinear points: \( \binom{3}{1} = 3 \) - Total combinations for this case: \( 21 \times 3 = 63 \) 3. **Select all 3 points from the non-collinear points**: - The number of ways to select 3 points from 3 non-collinear points: \( \binom{3}{3} = 1 \) - Total combinations for this case: \( 1 \) ### Step 4: Add all the combinations together Now, we add all the combinations from the three cases: - From case 1: 21 - From case 2: 63 - From case 3: 1 Total circles = \( 21 + 63 + 1 = 85 \) ### Conclusion The total number of circles that can be formed is **85**.
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