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6 equidistant vertical lines are drawn o...

6 equidistant vertical lines are drawn on a board. 6 equidistant horizontal lines are also drawn on the board cutting the 6 vertical lines, and the distance between any two consecutive horizontal lines is equal to that between any two consecutive vertical lines. What is the maximum number of squares thus formed?

A

A) 37

B

B) 55

C

C) 91

D

D) 225

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the maximum number of squares formed by 6 equidistant vertical lines and 6 equidistant horizontal lines, we can follow these steps: ### Step 1: Understand the Grid Formation We have 6 vertical lines and 6 horizontal lines. The intersection of these lines forms a grid. Each square is formed by selecting two vertical lines and two horizontal lines. ### Step 2: Count the Squares of Different Sizes We can form squares of various sizes within this grid. The sizes of squares we can form are: - 1x1 squares - 2x2 squares - 3x3 squares - 4x4 squares - 5x5 squares ### Step 3: Calculate the Number of Each Size of Square 1. **1x1 Squares**: - The number of 1x1 squares is determined by the number of ways to choose 2 vertical lines and 2 horizontal lines from the 6 lines. - The number of 1x1 squares = (6 - 1) * (6 - 1) = 5 * 5 = 25. 2. **2x2 Squares**: - The number of 2x2 squares = (6 - 2) * (6 - 2) = 4 * 4 = 16. 3. **3x3 Squares**: - The number of 3x3 squares = (6 - 3) * (6 - 3) = 3 * 3 = 9. 4. **4x4 Squares**: - The number of 4x4 squares = (6 - 4) * (6 - 4) = 2 * 2 = 4. 5. **5x5 Squares**: - The number of 5x5 squares = (6 - 5) * (6 - 5) = 1 * 1 = 1. ### Step 4: Sum All the Squares Now, we sum all the squares calculated: - Total squares = 25 (1x1) + 16 (2x2) + 9 (3x3) + 4 (4x4) + 1 (5x5) = 55. ### Conclusion The maximum number of squares that can be formed is **55**.
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