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With 17 consonants and 5 vowels the numb...

With 17 consonants and 5 vowels the number of words of four letters that can be formed having two different vowels in the middle and one consonant, repeated or different at each end is

A

5780

B

2890

C

5440

D

2720

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AI Generated Solution

The correct Answer is:
To solve the problem of forming four-letter words with specific conditions, we will follow these steps: ### Step-by-Step Solution 1. **Identify the structure of the word**: The word consists of four letters in the format: C V V C, where C represents consonants and V represents vowels. The two middle letters must be different vowels. 2. **Select the vowels**: We have 5 vowels to choose from, and we need to select 2 different vowels for the middle positions. The number of ways to choose 2 different vowels from 5 is given by the combination formula \( \binom{n}{r} \): \[ \text{Ways to choose 2 vowels} = \binom{5}{2} = \frac{5!}{2!(5-2)!} = \frac{5 \times 4}{2 \times 1} = 10 \] 3. **Arrange the vowels**: The two vowels selected can be arranged in the two middle positions in \( 2! \) ways: \[ \text{Ways to arrange 2 vowels} = 2! = 2 \] Therefore, the total ways to fill the middle positions with vowels is: \[ \text{Total ways for vowels} = 10 \times 2 = 20 \] 4. **Select the consonants**: For the first and last positions, we can use any of the 17 consonants. Since the consonants can be the same or different, we have: \[ \text{Ways to choose the first consonant} = 17 \quad \text{(any of the 17 consonants)} \] \[ \text{Ways to choose the last consonant} = 17 \quad \text{(any of the 17 consonants)} \] Thus, the total ways to fill the consonant positions is: \[ \text{Total ways for consonants} = 17 \times 17 = 289 \] 5. **Combine the choices**: The total number of four-letter words that can be formed is the product of the ways to choose and arrange the vowels and the ways to choose the consonants: \[ \text{Total number of words} = \text{Total ways for vowels} \times \text{Total ways for consonants} \] \[ \text{Total number of words} = 20 \times 289 = 5780 \] ### Final Answer The total number of four-letter words that can be formed is **5780**.
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