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The area of a circle is 38.5 sq. cm. Its...

The area of a circle is 38.5 sq. cm. Its circumference (in cm) is (use `pi = (22)/(7)`) :

A

22

B

24

C

26

D

32

Text Solution

AI Generated Solution

The correct Answer is:
To find the circumference of a circle given its area, we can follow these steps: ### Step 1: Write down the formula for the area of a circle. The area \( A \) of a circle is given by the formula: \[ A = \pi r^2 \] where \( r \) is the radius of the circle. ### Step 2: Substitute the given area into the formula. We know the area is \( 38.5 \, \text{sq. cm} \). Using \( \pi = \frac{22}{7} \), we can set up the equation: \[ 38.5 = \frac{22}{7} r^2 \] ### Step 3: Convert \( 38.5 \) into a fraction for easier calculations. We can express \( 38.5 \) as: \[ 38.5 = \frac{385}{10} \] ### Step 4: Clear the fraction by multiplying both sides by \( 10 \). Multiply both sides by \( 10 \) to eliminate the denominator: \[ 385 = \frac{22}{7} r^2 \times 10 \] This simplifies to: \[ 385 = \frac{220}{7} r^2 \] ### Step 5: Multiply both sides by \( 7 \) to eliminate the fraction. \[ 385 \times 7 = 220 r^2 \] Calculating \( 385 \times 7 \): \[ 2695 = 220 r^2 \] ### Step 6: Divide both sides by \( 220 \) to solve for \( r^2 \). \[ r^2 = \frac{2695}{220} \] ### Step 7: Simplify \( \frac{2695}{220} \). We can simplify this fraction: \[ r^2 = \frac{2695 \div 5}{220 \div 5} = \frac{539}{44} \] ### Step 8: Calculate \( r \) by taking the square root. \[ r = \sqrt{\frac{539}{44}} = \frac{\sqrt{539}}{\sqrt{44}} = \frac{\sqrt{539}}{2\sqrt{11}} \] ### Step 9: Calculate the circumference using the radius. The circumference \( C \) of a circle is given by: \[ C = 2 \pi r \] Substituting \( \pi = \frac{22}{7} \) and \( r = \frac{7}{2} \): \[ C = 2 \times \frac{22}{7} \times \frac{7}{2} \] ### Step 10: Simplify the expression for circumference. The \( 2 \) and \( \frac{7}{2} \) cancel out: \[ C = 22 \, \text{cm} \] ### Final Answer: The circumference of the circle is \( 22 \, \text{cm} \). ---
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KIRAN PUBLICATION-MENSURATION-Test Yourself
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