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A can go round a circular path 8 times i...

A can go round a circular path 8 times in 40 minutes. If the diameter of the circle is increased to 10 times the original diameter, the time required by A to go round the new path once travelling at the same speed as before is :

A

25 min

B

20 min

C

50 min

D

100 min

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find out how long it will take A to go around a new circular path after the diameter has been increased to 10 times the original diameter. Let's break it down step by step. ### Step 1: Determine the original diameter and circumference 1. A can go around the original circular path 8 times in 40 minutes. 2. The total distance covered in 8 rounds is equal to 8 times the circumference of the circle. 3. Let the original diameter be \( d \). The circumference \( C \) of the circle is given by: \[ C = \pi d \] 4. Therefore, the total distance covered in 8 rounds is: \[ \text{Total distance} = 8C = 8(\pi d) \] ### Step 2: Calculate the speed of A 1. The time taken to cover this distance is 40 minutes. 2. The speed \( S \) of A can be calculated as: \[ S = \frac{\text{Total distance}}{\text{Time}} = \frac{8(\pi d)}{40} = \frac{\pi d}{5} \text{ (in units of distance per minute)} \] ### Step 3: Determine the new diameter and circumference 1. The new diameter is 10 times the original diameter: \[ \text{New diameter} = 10d \] 2. The new circumference \( C' \) of the circle is: \[ C' = \pi \times \text{New diameter} = \pi (10d) = 10\pi d \] ### Step 4: Calculate the time taken to go around the new path once 1. The time taken \( T' \) to go around the new path once at the same speed \( S \) is given by: \[ T' = \frac{\text{New circumference}}{S} = \frac{10\pi d}{\frac{\pi d}{5}} \] 2. Simplifying this: \[ T' = 10\pi d \times \frac{5}{\pi d} = 10 \times 5 = 50 \text{ minutes} \] ### Conclusion Thus, the time required by A to go around the new path once is **50 minutes**. ---
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