Home
Class 14
MATHS
If the perimeter of a semicircular field...

If the perimeter of a semicircular field is 144m, then the diameter of the field is (take `pi = (22)/(7)`)

A

55m

B

30 m

C

28 m

D

56m

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the diameter of a semicircular field given that its perimeter is 144 meters. We'll use the value of π as \( \frac{22}{7} \). ### Step-by-Step Solution: 1. **Understand the Perimeter of a Semicircle**: The perimeter \( P \) of a semicircular field can be calculated using the formula: \[ P = \pi r + 2r \] where \( r \) is the radius of the semicircle. The term \( \pi r \) represents the curved part, and \( 2r \) represents the two straight edges (the diameter). 2. **Set Up the Equation**: Given that the perimeter is 144 meters, we can set up the equation: \[ \pi r + 2r = 144 \] 3. **Substitute the Value of π**: Substitute \( \pi \) with \( \frac{22}{7} \): \[ \frac{22}{7} r + 2r = 144 \] 4. **Combine the Terms**: To combine the terms, we need a common denominator. Rewrite \( 2r \) as \( \frac{14r}{7} \): \[ \frac{22r}{7} + \frac{14r}{7} = 144 \] This simplifies to: \[ \frac{36r}{7} = 144 \] 5. **Clear the Fraction**: Multiply both sides by 7 to eliminate the fraction: \[ 36r = 144 \times 7 \] Calculate \( 144 \times 7 \): \[ 36r = 1008 \] 6. **Solve for r**: Divide both sides by 36 to find \( r \): \[ r = \frac{1008}{36} \] Simplifying this gives: \[ r = 28 \text{ meters} \] 7. **Calculate the Diameter**: The diameter \( d \) of the semicircle is given by: \[ d = 2r \] Substituting the value of \( r \): \[ d = 2 \times 28 = 56 \text{ meters} \] ### Final Answer: The diameter of the semicircular field is **56 meters**. ---
Promotional Banner

Topper's Solved these Questions

  • MENSURATION

    KIRAN PUBLICATION|Exercise TYPE -II|386 Videos
  • MENSURATION

    KIRAN PUBLICATION|Exercise TYPE - III|21 Videos
  • LCM AND HCF

    KIRAN PUBLICATION|Exercise Test Yourself |18 Videos
  • MISCELLANEOUS

    KIRAN PUBLICATION|Exercise TYPE-VI|15 Videos

Similar Questions

Explore conceptually related problems

If the perimeter of a 180 m wide rectangular field is 840 m, then the area of the shield is

If the perimeter of a semicircular protractor is 36cm, find its diameter.

The perimeter of a circular field is 242m. The area of the field is

If the perimeter of a semicircular protractor is 66cm, Find the diameter of the protractor.

If the perimeter of a semicircular protractor is 66 cm, find the diameter of the protractor ("Take "pi=22//7)

If the diameter of a semicircular protractor is 14cm, then find its perimeter.

If the perimeter of a semicircular park is 360 m, then what is its area? (Take pi = 22/7 )

There is a rectangular tank of length 180 m and breadth 120 m in a circular field. If the area of the lad portion of the field is 40000 m^(2) , what is the radius of the field ? (Take pi = (22)/(7) )

The ratio between the area of a square and that of a circle, when the length of a side of the square is equal to that of the diameter of the circle, is (Take, pi = (22)/(7) )

KIRAN PUBLICATION-MENSURATION-Test Yourself
  1. If the perimeter of a semicircular field is 144m, then the diameter of...

    Text Solution

    |

  2. ABCD is a trapezium in which AB||CD and AB=2CD. If its diagonals inter...

    Text Solution

    |

  3. ABCD is a parallelogram, E and F are the mid-points of BC and CD. Find...

    Text Solution

    |

  4. Find the ratio of the areas of squares circumscribed about and inscrib...

    Text Solution

    |

  5. A sphere of radius r is incribed in a right circular cone whose slant ...

    Text Solution

    |

  6. The radius of each circle is 'a'. Then the area of the shaded portion ...

    Text Solution

    |

  7. The length of each side of a rhombus is equal to the length of the sid...

    Text Solution

    |

  8. In the figure given below, D is the diameter of each circle. What is t...

    Text Solution

    |

  9. Three equal circles of unit radius touch one another. Then the area of...

    Text Solution

    |

  10. Two goats tethered to diagonally opposite vertices of a field formed b...

    Text Solution

    |

  11. Find the area of the triangle inscribed in a circle circumscribed by a...

    Text Solution

    |

  12. From a thin metallic sheet in the shape of a trapezium ABCD in which A...

    Text Solution

    |

  13. AB and CD are parallel sides of a trapezium ABCD. Its diagonals inters...

    Text Solution

    |

  14. In the given figure, ABCd is a square of side 14 cm. Semicricles are d...

    Text Solution

    |

  15. A figure has a square of side 40 cm wih an circle in a circumcircle. T...

    Text Solution

    |

  16. A sqaure of side 4 cm is inscirbed in a circular quadrant such that on...

    Text Solution

    |

  17. The sum of length and breadth of a rectangle is 16 cm. A circle is cir...

    Text Solution

    |

  18. ABCD is a rhombus with side 10 cm and one of its diagonals BD equal to...

    Text Solution

    |

  19. The height of an equilateral triangle is 42 cm. A circle is drawn with...

    Text Solution

    |

  20. In an isosceles triangle, the lengh of each equal side is 1.5 times th...

    Text Solution

    |

  21. Four circles of equal radii are inscribed in a square of side 56 cm, t...

    Text Solution

    |