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If the perimeter of circle A is equal to...

If the perimeter of circle A is equal to perimeter of semi circle B, what is the ratio of their areas ?

A

`(pi + 2)^(2): 2pi^(2)`

B

`2pi^(2) : (pi + 2)^(2)`

C

`(pi + 2)^(2) : 4pi^(2)`

D

`4pi^(2) : (pi + 2)^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the areas of circle A and semicircle B given that their perimeters are equal. ### Step 1: Define the Perimeter of Circle A The perimeter (circumference) of a circle is given by the formula: \[ P_A = 2\pi r_A \] where \( r_A \) is the radius of circle A. ### Step 2: Define the Perimeter of Semicircle B The perimeter of a semicircle includes the curved part and the diameter. The formula for the perimeter of a semicircle is: \[ P_B = \pi r_B + 2r_B \] where \( r_B \) is the radius of semicircle B. This simplifies to: \[ P_B = \pi r_B + 2r_B = r_B(\pi + 2) \] ### Step 3: Set the Perimeters Equal According to the problem, the perimeters are equal: \[ 2\pi r_A = r_B(\pi + 2) \] ### Step 4: Solve for the Relationship Between Radii From the equation above, we can express \( r_B \) in terms of \( r_A \): \[ r_B = \frac{2\pi r_A}{\pi + 2} \] ### Step 5: Calculate the Areas Now, we will calculate the areas of circle A and semicircle B. - The area of circle A is given by: \[ A_A = \pi r_A^2 \] - The area of semicircle B is given by: \[ A_B = \frac{1}{2} \pi r_B^2 \] Substituting the expression for \( r_B \): \[ A_B = \frac{1}{2} \pi \left( \frac{2\pi r_A}{\pi + 2} \right)^2 \] \[ A_B = \frac{1}{2} \pi \cdot \frac{4\pi^2 r_A^2}{(\pi + 2)^2} \] \[ A_B = \frac{2\pi^3 r_A^2}{(\pi + 2)^2} \] ### Step 6: Find the Ratio of the Areas Now, we find the ratio of the areas \( \frac{A_A}{A_B} \): \[ \frac{A_A}{A_B} = \frac{\pi r_A^2}{\frac{2\pi^3 r_A^2}{(\pi + 2)^2}} \] \[ = \frac{(\pi + 2)^2}{2\pi^2} \] ### Final Step: Simplifying the Ratio Thus, the ratio of the areas of circle A to semicircle B is: \[ \frac{A_A}{A_B} = \frac{(\pi + 2)^2}{2\pi^2} \] ### Conclusion The ratio of the areas of circle A to semicircle B is: \[ \frac{(\pi + 2)^2}{2\pi^2} \]
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