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The lengths of the two diagonals of a rh...

The lengths of the two diagonals of a rhombus are 6 cm and 8 cm. Find the length of its perimeter (in cm).

A

20

B

10

C

40

D

30

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The correct Answer is:
To find the perimeter of a rhombus given the lengths of its diagonals, we can follow these steps: ### Step 1: Identify the lengths of the diagonals Let the lengths of the diagonals be: - AC = 6 cm - BD = 8 cm ### Step 2: Calculate the half-lengths of the diagonals Since the diagonals of a rhombus bisect each other at right angles, we can find the lengths of the segments formed by the intersection point (let's call it O): - AO = AC / 2 = 6 cm / 2 = 3 cm - BO = BD / 2 = 8 cm / 2 = 4 cm ### Step 3: Use the Pythagorean theorem to find the length of a side of the rhombus In triangle AOB, we can apply the Pythagorean theorem: - AB² = AO² + BO² - AB² = (3 cm)² + (4 cm)² - AB² = 9 cm² + 16 cm² - AB² = 25 cm² - AB = √25 cm² = 5 cm ### Step 4: Calculate the perimeter of the rhombus The perimeter P of a rhombus is given by the formula: - P = 4 × side length - P = 4 × AB - P = 4 × 5 cm = 20 cm ### Final Answer The perimeter of the rhombus is 20 cm. ---
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