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There is a rectangular tank of length 18...

There is a rectangular tank of length 180 m and breadth 120 m in a circular field. If the area of the lad portion of the field is `40000 m^(2)`, what is the radius of the field ? (Take `pi = (22)/(7)`)

A

130m

B

135m

C

140m

D

145m

Text Solution

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The correct Answer is:
To find the radius of the circular field surrounding a rectangular tank, we can follow these steps: ### Step 1: Calculate the area of the rectangular tank. The area \( A \) of a rectangle is given by the formula: \[ A = \text{length} \times \text{breadth} \] Given the length \( L = 180 \, m \) and breadth \( B = 120 \, m \): \[ A = 180 \, m \times 120 \, m = 21600 \, m^2 \] ### Step 2: Calculate the total area of the circular field. We know that the area of the land portion of the field is \( 40000 \, m^2 \). Therefore, the total area of the circular field \( A_{circle} \) can be calculated as: \[ A_{circle} = \text{Area of the tank} + \text{Area of the land portion} \] \[ A_{circle} = 21600 \, m^2 + 40000 \, m^2 = 61600 \, m^2 \] ### Step 3: Set up the equation for the area of the circle. The area \( A \) of a circle is given by the formula: \[ A = \pi r^2 \] Substituting the known area of the circle: \[ 61600 = \frac{22}{7} r^2 \] ### Step 4: Solve for \( r^2 \). To isolate \( r^2 \), we can multiply both sides by \( \frac{7}{22} \): \[ r^2 = 61600 \times \frac{7}{22} \] Calculating the right-hand side: \[ r^2 = 61600 \times \frac{7}{22} = 61600 \times 0.318181818 \approx 21600 \] ### Step 5: Calculate \( r \). Now, we take the square root of both sides to find \( r \): \[ r = \sqrt{2800} \] Calculating \( r \): \[ r = \sqrt{2800} \approx 52.92 \, m \] ### Step 6: Final answer. Thus, the radius of the circular field is approximately: \[ r \approx 140 \, m \]
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