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The area of the incircle of an equilater...

The area of the incircle of an equilateral triangle of side 42 cm is (Take `pi = (22)/(7)`):

A

`231 cm^(2)`

B

`462 cm^(2)`

C

`22sqrt(3) cm^(2)`

D

`924 cm^(2)`

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AI Generated Solution

The correct Answer is:
To find the area of the incircle of an equilateral triangle with a side length of 42 cm, we can follow these steps: ### Step 1: Find the radius of the incircle The formula for the radius (r) of the incircle of an equilateral triangle is given by: \[ r = \frac{s \sqrt{3}}{6} \] where \(s\) is the side length of the triangle. Given that the side length \(s = 42\) cm, we can substitute this value into the formula. \[ r = \frac{42 \sqrt{3}}{6} \] ### Step 2: Simplify the expression for the radius Now, simplify the expression: \[ r = \frac{42}{6} \sqrt{3} = 7 \sqrt{3} \text{ cm} \] ### Step 3: Calculate the area of the incircle The area (A) of the incircle can be calculated using the formula: \[ A = \pi r^2 \] Substituting the value of \(r\) into the area formula: \[ A = \pi (7 \sqrt{3})^2 \] ### Step 4: Simplify the area expression Now, calculate \( (7 \sqrt{3})^2 \): \[ (7 \sqrt{3})^2 = 49 \times 3 = 147 \] So, the area becomes: \[ A = \pi \times 147 \] ### Step 5: Substitute the value of \(\pi\) Now, substitute \(\pi = \frac{22}{7}\): \[ A = \frac{22}{7} \times 147 \] ### Step 6: Calculate the area To simplify: \[ A = 22 \times 21 = 462 \text{ cm}^2 \] ### Final Answer The area of the incircle of the equilateral triangle is \(462 \text{ cm}^2\). ---
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