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A square and an equilateral triangle are...

A square and an equilateral triangle are drawn on the same base. The ratio of their area is

A

`2:1`

B

`1:1`

C

`sqrt(3):4`

D

`4 : sqrt(3)`

Text Solution

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The correct Answer is:
To find the ratio of the areas of a square and an equilateral triangle drawn on the same base, we can follow these steps: ### Step 1: Define the side length Let the side length of the square and the base of the equilateral triangle be denoted as \( a \). ### Step 2: Calculate the area of the square The area \( A_{\text{square}} \) of the square is given by the formula: \[ A_{\text{square}} = a^2 \] ### Step 3: Calculate the height of the equilateral triangle For an equilateral triangle with side length \( a \), the height \( h \) can be calculated using the formula: \[ h = \frac{\sqrt{3}}{2} a \] ### Step 4: Calculate the area of the equilateral triangle The area \( A_{\text{triangle}} \) of the equilateral triangle is given by the formula: \[ A_{\text{triangle}} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times a \times h \] Substituting the height from Step 3: \[ A_{\text{triangle}} = \frac{1}{2} \times a \times \left(\frac{\sqrt{3}}{2} a\right) = \frac{\sqrt{3}}{4} a^2 \] ### Step 5: Find the ratio of the areas Now, we can find the ratio of the area of the square to the area of the equilateral triangle: \[ \text{Ratio} = \frac{A_{\text{square}}}{A_{\text{triangle}}} = \frac{a^2}{\frac{\sqrt{3}}{4} a^2} \] The \( a^2 \) terms cancel out: \[ \text{Ratio} = \frac{1}{\frac{\sqrt{3}}{4}} = \frac{4}{\sqrt{3}} \] ### Step 6: Simplify the ratio Thus, the ratio of the area of the square to the area of the equilateral triangle is: \[ \text{Ratio} = 4 : \sqrt{3} \] ### Final Answer The ratio of the areas of the square and the equilateral triangle is \( 4 : \sqrt{3} \). ---
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