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If the circumference of a circle is incr...

If the circumference of a circle is increased by 50% then the area will be increased by

A

(a) `50%`

B

(b) `75%`

C

(c) `100%`

D

(d) `125%`

Text Solution

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The correct Answer is:
To solve the problem of how much the area of a circle increases when its circumference is increased by 50%, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between circumference and radius**: The circumference \( C \) of a circle is given by the formula: \[ C = 2\pi R \] where \( R \) is the radius of the circle. 2. **Calculate the new circumference**: If the circumference is increased by 50%, the new circumference \( C' \) can be calculated as: \[ C' = C + 0.5C = 1.5C = 1.5 \times 2\pi R = 3\pi R \] 3. **Find the new radius**: The new circumference \( C' \) can also be expressed in terms of the new radius \( R' \): \[ C' = 2\pi R' \] Setting the two expressions for \( C' \) equal gives: \[ 3\pi R = 2\pi R' \] Dividing both sides by \( 2\pi \): \[ R' = \frac{3R}{2} \] 4. **Calculate the old area**: The area \( A \) of the original circle is given by: \[ A = \pi R^2 \] 5. **Calculate the new area**: The area \( A' \) of the new circle with radius \( R' \) is: \[ A' = \pi (R')^2 = \pi \left(\frac{3R}{2}\right)^2 = \pi \left(\frac{9R^2}{4}\right) = \frac{9\pi R^2}{4} \] 6. **Find the increase in area**: The increase in area \( \Delta A \) is: \[ \Delta A = A' - A = \frac{9\pi R^2}{4} - \pi R^2 = \frac{9\pi R^2}{4} - \frac{4\pi R^2}{4} = \frac{5\pi R^2}{4} \] 7. **Calculate the percentage increase in area**: The percentage increase in area can be calculated as: \[ \text{Percentage Increase} = \left(\frac{\Delta A}{A}\right) \times 100 = \left(\frac{\frac{5\pi R^2}{4}}{\pi R^2}\right) \times 100 = \left(\frac{5}{4}\right) \times 100 = 125\% \] ### Conclusion: Thus, if the circumference of a circle is increased by 50%, then the area will be increased by **125%**.
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