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If area of an equilateral triangle is a ...

If area of an equilateral triangle is a and height b, then value of `(b^(2))/(a)` is

A

3

B

`(1)/(3)`

C

`sqrt(3)`

D

`(1)/(sqrt(3))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \(\frac{b^2}{a}\) where \(a\) is the area of an equilateral triangle and \(b\) is its height. ### Step-by-Step Solution: 1. **Understand the formulas for area and height of an equilateral triangle:** - The area \(A\) of an equilateral triangle with side length \(s\) is given by: \[ A = \frac{\sqrt{3}}{4} s^2 \] - The height \(h\) of an equilateral triangle with side length \(s\) is given by: \[ h = \frac{\sqrt{3}}{2} s \] 2. **Substitute the height into the expression for \(b^2\):** - Since \(b\) is the height, we have: \[ b = h = \frac{\sqrt{3}}{2} s \] - Now, calculate \(b^2\): \[ b^2 = \left(\frac{\sqrt{3}}{2} s\right)^2 = \frac{3}{4} s^2 \] 3. **Substitute the area into the expression for \(a\):** - We already have the area \(a\): \[ a = A = \frac{\sqrt{3}}{4} s^2 \] 4. **Now, substitute \(b^2\) and \(a\) into the expression \(\frac{b^2}{a}\):** \[ \frac{b^2}{a} = \frac{\frac{3}{4} s^2}{\frac{\sqrt{3}}{4} s^2} \] 5. **Simplify the expression:** - The \(s^2\) terms cancel out: \[ \frac{b^2}{a} = \frac{3/4}{\sqrt{3}/4} = \frac{3}{\sqrt{3}} \] - Simplifying further: \[ \frac{3}{\sqrt{3}} = \sqrt{3} \] 6. **Final Result:** - Therefore, the value of \(\frac{b^2}{a}\) is: \[ \frac{b^2}{a} = \sqrt{3} \] ### Conclusion: The final answer is \(\sqrt{3}\).
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