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a and b are two side adjacent to the right angle of a right-angled triangle and p is the perpendicular drawn to the hypotenuse from the opposite vertex. Then `p^(2)` is equal to

A

`a^(2) + b^(2)`

B

`(1)/(a^(2)) + (1)/(b^(2))`

C

`(a^(2)b^(2))/(a^(2)+b^(2))`

D

`a^(2) - b^(2)`

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The correct Answer is:
To solve the problem, we need to find the value of \( p^2 \) where \( p \) is the perpendicular drawn from the opposite vertex to the hypotenuse of a right-angled triangle with sides \( a \) and \( b \). ### Step-by-Step Solution: 1. **Identify the Triangle and its Components**: - Let \( \triangle ABC \) be a right-angled triangle where \( \angle ABC = 90^\circ \). - Let \( AB = c \) (the hypotenuse), \( BC = a \), and \( AC = b \). - The point \( P \) is the foot of the perpendicular drawn from vertex \( A \) to the hypotenuse \( BC \). 2. **Area of Triangle Using Base and Height**: - The area of triangle \( ABC \) can be calculated using the two sides adjacent to the right angle: \[ \text{Area} = \frac{1}{2} \times a \times b \] 3. **Area of Triangle Using Hypotenuse and Height**: - The area can also be expressed using the hypotenuse \( c \) and the height \( p \): \[ \text{Area} = \frac{1}{2} \times c \times p \] 4. **Equating the Two Area Expressions**: - Since both expressions represent the same area, we can set them equal to each other: \[ \frac{1}{2} \times a \times b = \frac{1}{2} \times c \times p \] - Simplifying this gives: \[ ab = cp \quad \text{(Equation 1)} \] 5. **Using Pythagorean Theorem**: - According to the Pythagorean theorem: \[ c^2 = a^2 + b^2 \] - Therefore, we can express \( c \) as: \[ c = \sqrt{a^2 + b^2} \] 6. **Substituting \( c \) into Equation 1**: - Substitute \( c \) into Equation 1: \[ ab = \sqrt{a^2 + b^2} \cdot p \] 7. **Solving for \( p \)**: - Rearranging gives: \[ p = \frac{ab}{\sqrt{a^2 + b^2}} \] 8. **Finding \( p^2 \)**: - Now, squaring both sides to find \( p^2 \): \[ p^2 = \left(\frac{ab}{\sqrt{a^2 + b^2}}\right)^2 \] - This simplifies to: \[ p^2 = \frac{a^2b^2}{a^2 + b^2} \] ### Conclusion: Thus, the value of \( p^2 \) is: \[ p^2 = \frac{a^2b^2}{a^2 + b^2} \]
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