Home
Class 14
MATHS
A farmer's land is in the shape of a tra...

A farmer's land is in the shape of a trapezium which has its parallel sides measuring 2.56 yards and 3.44 yeards and the distance between the parallel sides in 1.44 yards. The cost of ploughing the land is Rs. 1800 per square yard. What amount will (in Rs.) have to be spent in order to plough the entire land ?

A

3672

B

6732

C

7776

D

8214

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will calculate the area of the trapezium and then determine the cost of ploughing the land. ### Step 1: Identify the dimensions of the trapezium The lengths of the parallel sides are: - Side 1 (a) = 2.56 yards - Side 2 (b) = 3.44 yards The distance between the parallel sides (height, h) = 1.44 yards. ### Step 2: Calculate the area of the trapezium The formula for the area (A) of a trapezium is given by: \[ A = \frac{(a + b) \times h}{2} \] Substituting the values: \[ A = \frac{(2.56 + 3.44) \times 1.44}{2} \] ### Step 3: Calculate the sum of the parallel sides First, calculate \(2.56 + 3.44\): \[ 2.56 + 3.44 = 6.00 \] ### Step 4: Substitute the sum into the area formula Now substitute this sum back into the area formula: \[ A = \frac{6.00 \times 1.44}{2} \] ### Step 5: Calculate the area Now compute \(6.00 \times 1.44\): \[ 6.00 \times 1.44 = 8.64 \] Now divide by 2: \[ A = \frac{8.64}{2} = 4.32 \text{ square yards} \] ### Step 6: Calculate the cost of ploughing The cost of ploughing per square yard is Rs. 1800. Therefore, the total cost (C) is: \[ C = A \times \text{cost per square yard} = 4.32 \times 1800 \] ### Step 7: Compute the total cost Now calculate \(4.32 \times 1800\): \[ 4.32 \times 1800 = 7776 \text{ Rs.} \] ### Final Answer The amount that will have to be spent in order to plough the entire land is Rs. 7776. ---
Promotional Banner

Topper's Solved these Questions

  • MENSURATION

    KIRAN PUBLICATION|Exercise TYPE - III|21 Videos
  • MENSURATION

    KIRAN PUBLICATION|Exercise TYPE - IV|169 Videos
  • MENSURATION

    KIRAN PUBLICATION|Exercise Test Yourself|28 Videos
  • LCM AND HCF

    KIRAN PUBLICATION|Exercise Test Yourself |18 Videos
  • MISCELLANEOUS

    KIRAN PUBLICATION|Exercise TYPE-VI|15 Videos

Similar Questions

Explore conceptually related problems

A farmer wants to purchase a land which is in the shape of trapezium. The lengths of its parallel sides are 18 ft, 15 ft, and perpendicular distance between them is 20 ft. Find the total cost of the field at the rate of Rs.2000 per sq. ft.

A field is in the shape of a trapezium having parallel sides 90 m and 30 m. These sides meet the thired side at right angles. The length of the fourth side is 100 m. If it costs Rs. 5 to plough 1 m^(2) of the field, find the total cost of ploughing the field.

A field is in the shape of a trapezium having parallel sides 90 m and 30 m. These sides meet the third side at right angles. The length of the fourth side is 100 m. If it costs ruppe 4 to plough 1 m^(2) of the field, find the total cost of ploughing the field.

A wall is of the form of a trapezium with height 4m and parallel sides being 3m and 5m. What is the cost of painting the wall, if the rate of painting is Rs 25- per square metre.

The area of a field in the shape of trapezium measures 1440 m^(2) . The perpendicular distance between its parallel sides is 24 m. If the ratio of the parallel sides is 5 : 3, the length of the longer parallel side is :

A plot is in the shape of a trapezium. The parallel sides of the plot are 20 m and 16 m long, and the distance between them is 8 m. A square plot has the same area as the trapezium. A pit of dimensions 2.4 m long, 1.5 m wide, and 1 m deep is dug inside the trapezium plot and the soil is spread uniformly on the square plot. Find the rise in the level of hte plot.

The area of a field in the shape of a trapezium measures 1440 m2. The perpendicular distance between its parallel sides is 24 m. If the ratio of the parallel sides is 5 : 3, the length of the longer parallel side is (a) 45 m (b) 60 m (c) 75 m (d) 120 m

KIRAN PUBLICATION-MENSURATION-TYPE -II
  1. Two identical circles intersect so that their centres and the poits at...

    Text Solution

    |

  2. In DeltaPQR, PS and PT are bisectors of angleQPR and angleQPS respecti...

    Text Solution

    |

  3. A farmer's land is in the shape of a trapezium which has its parallel ...

    Text Solution

    |

  4. If medians of a triangle have lengths 18 cm, 24 cm and 30 cm, what is ...

    Text Solution

    |

  5. Two smaller circles touch a large circle internally and pass through t...

    Text Solution

    |

  6. In the given figure, PQRS is a trapezium in which PM ||NS= 9cm, PS= 12...

    Text Solution

    |

  7. The smaller diagonal of a rhombus is equal to length of its sides. If ...

    Text Solution

    |

  8. In the given figure, triangle ABC is drawn such that AB is tangent to ...

    Text Solution

    |

  9. In triangle ABC, AD, BE and CF are the medians intersecting at point G...

    Text Solution

    |

  10. The length of diagonal of a square is 9sqrt(2) cm. The square is resha...

    Text Solution

    |

  11. The tangents drawn at point A and B of a circle with centre O, meet at...

    Text Solution

    |

  12. In DeltaPQR, PS and PT are bisectors of angleQPR and angleQPS respecti...

    Text Solution

    |

  13. What is the area of a rectangle if its diagonal is 51 cm and one of it...

    Text Solution

    |

  14. D and E are points on sides AB and AC of Delta ABC. DE is parallel to ...

    Text Solution

    |

  15. What is the area (in sq cm.) of the regular hexagon side 14 cm ?

    Text Solution

    |

  16. What is the area (in sq. cm.) of a rhombus if the lengths of the diago...

    Text Solution

    |

  17. The areas of two similar triangles Delta ABC and Delta PQR are 36 sq. ...

    Text Solution

    |

  18. D and E are points on sides AB and AC of Delta ABC. DE is parallel to ...

    Text Solution

    |

  19. Points P and Q lie on sides AB and AC of triangle ABC respectively suc...

    Text Solution

    |

  20. Three circles of raidus 21 cm are placed in such a way that each circl...

    Text Solution

    |