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The area of the base of a right circular...

The area of the base of a right circular cone is `(1408)/(7) cm^(2)` and its height is 6 cm. Taking `pi = (22)/(7)`, what will be the curved surface area of the cone ?

A

`(1760)/(7) cm^(2)`

B

`(1067)/(7) cm^(2)`

C

`(1670)/(7) cm^(2)`

D

`(7160)/(7) cm^(2)`

Text Solution

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The correct Answer is:
To find the curved surface area (CSA) of the right circular cone, we will follow these steps: ### Step 1: Understand the given data We are given: - Area of the base of the cone = \( \frac{1408}{7} \, \text{cm}^2 \) - Height of the cone (h) = 6 cm - Value of \( \pi = \frac{22}{7} \) ### Step 2: Use the area of the base to find the radius The area of the base of a cone is given by the formula: \[ \text{Area} = \pi r^2 \] Substituting the values we have: \[ \frac{1408}{7} = \frac{22}{7} r^2 \] To eliminate \( \frac{7}{7} \), we can multiply both sides by 7: \[ 1408 = 22 r^2 \] Now, divide both sides by 22 to solve for \( r^2 \): \[ r^2 = \frac{1408}{22} \] Calculating \( \frac{1408}{22} \): \[ r^2 = 64 \] Taking the square root to find \( r \): \[ r = \sqrt{64} = 8 \, \text{cm} \] ### Step 3: Calculate the slant height (l) The slant height \( l \) can be calculated using the Pythagorean theorem: \[ l = \sqrt{h^2 + r^2} \] Substituting the values of \( h \) and \( r \): \[ l = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 \, \text{cm} \] ### Step 4: Calculate the curved surface area (CSA) The formula for the curved surface area of a cone is: \[ \text{CSA} = \pi r l \] Substituting the values of \( \pi \), \( r \), and \( l \): \[ \text{CSA} = \frac{22}{7} \times 8 \times 10 \] Calculating this: \[ \text{CSA} = \frac{22 \times 80}{7} = \frac{1760}{7} \, \text{cm}^2 \] ### Final Answer The curved surface area of the cone is: \[ \text{CSA} = \frac{1760}{7} \, \text{cm}^2 \] ---
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