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The radius and height of a cylinder are ...

The radius and height of a cylinder are in the ratio 5:7 and ts volume is `550 cm^(3)`. Calculate its curved surface area in sq. cm.

A

110

B

444

C

220

D

616

Text Solution

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The correct Answer is:
To solve the problem step by step, we will follow the given information about the cylinder's dimensions and its volume. ### Step 1: Understand the given ratio of radius and height The radius (r) and height (h) of the cylinder are in the ratio of 5:7. This means we can express them in terms of a variable \( x \): - Let \( r = 5x \) - Let \( h = 7x \) ### Step 2: Write the formula for the volume of the cylinder The volume \( V \) of a cylinder is given by the formula: \[ V = \pi r^2 h \] We know that the volume is \( 550 \, \text{cm}^3 \). ### Step 3: Substitute the expressions for r and h into the volume formula Substituting \( r \) and \( h \) into the volume formula gives: \[ 550 = \pi (5x)^2 (7x) \] This simplifies to: \[ 550 = \pi (25x^2)(7x) = 175\pi x^3 \] ### Step 4: Substitute the value of \(\pi\) Using \( \pi \approx \frac{22}{7} \): \[ 550 = 175 \left(\frac{22}{7}\right) x^3 \] ### Step 5: Solve for \( x^3 \) To isolate \( x^3 \), we multiply both sides by \( 7 \) and divide by \( 175 \): \[ 550 \times 7 = 175 \times 22 x^3 \] \[ 3850 = 3850 x^3 \] \[ x^3 = 1 \] Taking the cube root gives: \[ x = 1 \] ### Step 6: Find the values of r and h Now that we have \( x \): - \( r = 5x = 5 \times 1 = 5 \, \text{cm} \) - \( h = 7x = 7 \times 1 = 7 \, \text{cm} \) ### Step 7: Calculate the curved surface area (CSA) The formula for the curved surface area of a cylinder is: \[ \text{CSA} = 2\pi rh \] Substituting the values of \( r \) and \( h \): \[ \text{CSA} = 2 \times \frac{22}{7} \times 5 \times 7 \] ### Step 8: Simplify the expression Calculating the CSA: \[ \text{CSA} = 2 \times \frac{22}{7} \times 35 \] \[ = \frac{2 \times 22 \times 35}{7} \] \[ = \frac{1540}{7} = 220 \, \text{cm}^2 \] ### Final Answer The curved surface area of the cylinder is \( 220 \, \text{cm}^2 \). ---
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