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If the volume of two cubes are in the ra...

If the volume of two cubes are in the ratio 27 : 64, then the ratio of their total surface area is :

A

a)`27:64`

B

b)`3:4`

C

c)`9:16`

D

d)`3:8`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the total surface area of two cubes given the ratio of their volumes. ### Step 1: Understand the relationship between volume and side length of a cube The volume \( V \) of a cube with side length \( a \) is given by the formula: \[ V = a^3 \] ### Step 2: Let the side lengths of the two cubes be \( a_1 \) and \( a_2 \) Given that the volumes of the two cubes are in the ratio 27:64, we can express this as: \[ \frac{V_1}{V_2} = \frac{27}{64} \] This means: \[ \frac{a_1^3}{a_2^3} = \frac{27}{64} \] ### Step 3: Take the cube root of both sides To find the ratio of the side lengths, we take the cube root of both sides: \[ \frac{a_1}{a_2} = \frac{\sqrt[3]{27}}{\sqrt[3]{64}} = \frac{3}{4} \] ### Step 4: Calculate the total surface area of the cubes The total surface area \( S \) of a cube with side length \( a \) is given by the formula: \[ S = 6a^2 \] Thus, the total surface areas of the two cubes are: \[ S_1 = 6a_1^2 \quad \text{and} \quad S_2 = 6a_2^2 \] ### Step 5: Find the ratio of the total surface areas Now we can find the ratio of the total surface areas: \[ \frac{S_1}{S_2} = \frac{6a_1^2}{6a_2^2} = \frac{a_1^2}{a_2^2} \] Using the ratio of the side lengths we found earlier: \[ \frac{S_1}{S_2} = \left(\frac{a_1}{a_2}\right)^2 = \left(\frac{3}{4}\right)^2 = \frac{9}{16} \] ### Final Answer Therefore, the ratio of their total surface areas is: \[ \frac{9}{16} \] ---
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