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The volume of a cuboid is twice the volu...

The volume of a cuboid is twice the volume of a cube. If the dimensions of the cuboid are 9 cm, 8 c and 6 cm, the total surface are of the cube is :

A

`72 cm^(2)`

B

`216 cm^(2)`

C

`432 cm^(2)`

D

`108 cm^(2)`

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The correct Answer is:
To solve the problem, we need to find the total surface area of a cube given that the volume of a cuboid is twice the volume of that cube. The dimensions of the cuboid are provided as 9 cm, 8 cm, and 6 cm. ### Step-by-Step Solution: 1. **Calculate the Volume of the Cuboid:** The formula for the volume of a cuboid is given by: \[ \text{Volume of Cuboid} = \text{Length} \times \text{Breadth} \times \text{Height} \] Substituting the given dimensions: \[ \text{Volume of Cuboid} = 9 \, \text{cm} \times 8 \, \text{cm} \times 6 \, \text{cm} \] \[ = 432 \, \text{cm}^3 \] 2. **Relate the Volume of the Cuboid to the Volume of the Cube:** According to the problem, the volume of the cuboid is twice the volume of the cube: \[ \text{Volume of Cuboid} = 2 \times \text{Volume of Cube} \] Therefore, we can express the volume of the cube as: \[ \text{Volume of Cube} = \frac{\text{Volume of Cuboid}}{2} = \frac{432 \, \text{cm}^3}{2} = 216 \, \text{cm}^3 \] 3. **Find the Side Length of the Cube:** The volume of a cube is given by: \[ \text{Volume of Cube} = \text{side}^3 \] Setting this equal to the volume we found: \[ \text{side}^3 = 216 \, \text{cm}^3 \] To find the side length, we take the cube root: \[ \text{side} = \sqrt[3]{216} \] Since \(6 \times 6 \times 6 = 216\), we find: \[ \text{side} = 6 \, \text{cm} \] 4. **Calculate the Total Surface Area of the Cube:** The total surface area (TSA) of a cube is given by: \[ \text{TSA} = 6 \times (\text{side})^2 \] Substituting the side length we found: \[ \text{TSA} = 6 \times (6 \, \text{cm})^2 = 6 \times 36 \, \text{cm}^2 = 216 \, \text{cm}^2 \] ### Final Answer: The total surface area of the cube is: \[ \text{TSA} = 216 \, \text{cm}^2 \]
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