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A right circular cylidner and a cone hav...

A right circular cylidner and a cone have equal base radius and equal height. If their curved surface are in the ratio 8:5, then the radius of the base to the height are in the ratio :

A

`2:3`

B

`4:3`

C

`3:4`

D

`3:2`

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The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the given information We have a right circular cylinder and a cone with equal base radius \( R \) and equal height \( H \). The curved surface areas of the cylinder and cone are in the ratio \( 8:5 \). ### Step 2: Write the formulas for the curved surface areas The curved surface area (CSA) of a cylinder is given by: \[ \text{CSA}_{\text{cylinder}} = 2\pi R H \] The curved surface area of a cone is given by: \[ \text{CSA}_{\text{cone}} = \pi R L \] where \( L \) is the slant height of the cone. ### Step 3: Set up the ratio of the curved surface areas According to the problem, we have: \[ \frac{\text{CSA}_{\text{cylinder}}}{\text{CSA}_{\text{cone}}} = \frac{8}{5} \] Substituting the formulas, we get: \[ \frac{2\pi R H}{\pi R L} = \frac{8}{5} \] ### Step 4: Simplify the equation We can cancel \( \pi R \) from both sides (assuming \( R \neq 0 \)): \[ \frac{2H}{L} = \frac{8}{5} \] ### Step 5: Cross-multiply to find a relationship between \( H \) and \( L \) Cross-multiplying gives: \[ 2H \cdot 5 = 8L \quad \Rightarrow \quad 10H = 8L \quad \Rightarrow \quad \frac{H}{L} = \frac{8}{10} = \frac{4}{5} \] ### Step 6: Relate the slant height \( L \) to the radius \( R \) and height \( H \) The slant height \( L \) of the cone can be calculated using the Pythagorean theorem: \[ L = \sqrt{H^2 + R^2} \] ### Step 7: Substitute \( L \) in the ratio From \( \frac{H}{L} = \frac{4}{5} \), we can substitute \( L \): \[ \frac{H}{\sqrt{H^2 + R^2}} = \frac{4}{5} \] ### Step 8: Cross-multiply and square both sides Cross-multiplying gives: \[ 5H = 4\sqrt{H^2 + R^2} \] Squaring both sides results in: \[ 25H^2 = 16(H^2 + R^2) \] Expanding and rearranging gives: \[ 25H^2 = 16H^2 + 16R^2 \quad \Rightarrow \quad 9H^2 = 16R^2 \] ### Step 9: Find the ratio of \( R \) to \( H \) Dividing both sides by \( H^2 \) and rearranging gives: \[ \frac{R^2}{H^2} = \frac{9}{16} \quad \Rightarrow \quad \frac{R}{H} = \frac{3}{4} \] ### Conclusion Thus, the ratio of the radius of the base to the height is: \[ \frac{R}{H} = \frac{3}{4} \]
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