In the given figure ABCD is a trapezium with AB || DC. E and F are respectively midpoint of AD and BC. Prove that, `EF=1/(2)(AB+CD)`

In the given figure. ABCD is a trapezium in which AB|| DC and E is the mid-point of AD, if EF||DC, then show that EF=(1)/(2)(AB+DC) .

In the given figure ABCD is a trapezium with AB || Dc and AD = BC prove that angleA=angleB

In the given figure ABCD is a trapezium with AB || Dc and AD = BC prove that angleC=angleD

In the given figure ABCD is a trapezium with AB || Dc and AD = BC prove that DeltaABC~~DeltaBAD

In the given figure ABCD is a trapezium with AB || Dc and AD = BC prove that diagonal AC = diagonal BD

ABCD is a trapezium, in which AD||BC, E and F are the mid-points of AB and CD respectively, then EF is:

ABCD is a trapezium in which AB |DC,AB=16cm and DC=24cm. If E and Fare respectively the midpoints of AD and BC prove that ar(ABFE)=(9)/(11)ar(EFCD)

In the given figure ABCD is a parallelogram in which AB||CD and E and F are the mid points of AB and BC respectively. What is the area of angleBEF ?

In a trapezium ABCD, if E and F be the mid-points of diagonal AC and BD respectively. Prove that EF=1/2(AB-CD).